I have an Ashdown MAG300 C-115 combo. In the manual it says minimum impedance at 4 ohms. Does that mean I should get a 4 ohms cab or an 8 ohms cab?
You have the combo, and I'm pretty sure it already has an 8 ohm cab attached to it. Therefore, you need another 8 ohm cabs to lower it to 4 ohms. An 8 and a 4 gives 2 and 2 3rds ohms.
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I was looking at a used Warwick Vampyre LTD 5'er for about \$200. I went home to grab my wallet and came back and some jerk with an epic beard got it already..
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An 8 and a 4 gives 2 and 2 3rds ohms.

What? LOL
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The equivalent resistance of the two cabs in parallel would be 1/req=1/8+1/4, which equals 3/8, when you take the inverse of that you get the equivalent resistance, so the inverse is 8/3 ohms, or 2 and 2/3 ohms, as he said.
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What? LOL

Don't worry, you're a guitar player - you'll probably never ever have to worry about that.
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I was looking at a used Warwick Vampyre LTD 5'er for about \$200. I went home to grab my wallet and came back and some jerk with an epic beard got it already..
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The equivalent resistance of the two cabs in parallel would be 1/req=1/8+1/4, which equals 3/8, when you take the inverse of that you get the equivalent resistance, so the inverse is 8/3 ohms, or 2 and 2/3 ohms, as he said.

I'm taking physics now and was figuring out how that worked during class. Must say I was proud of myself when I realized how it worked . I always just had it memorized that 8+8=4 and 8+4=2 2/3.