#1

# 0 to 9

ABCD X 4 = DCBA

X means multiplication

Enjoy

ABCD X 4 = DCBA

X means multiplication

Enjoy

#2

I don't see anything to be done here....?

#3

Are we supposed to find out the values of A, B, C, and D?

#4

wait.... ABCD are four different digits in one number, and the final number is the reverse of those digits?

You should've explained that, fool.

You should've explained that, fool.

#5

Oh, hey, more Spam.

#6

I thought some people here know more than just Guitar

Here is the Answer LOL!!

2178 * 4 = 8712

'a' must be 1 or 2 or else a 5-digit product would be formed.

but 'a' cant be 1 since d * 4 ends in 'a' and so 'a' must be even. so 'a' is 2

d must then be 3 or 8 since 4*d ends in 2. but d cant be 3 because 4*a (plus any carry) equals d so d must be at least 4. so d is 8.

at this point you can just try the other numbers for c and see what b must be. only the one combination works.

(or, if you notice that there is no carry digit with 4*b, (since 2*4=8 already) b must be 0 or 1 (2 is used already), and 0 wont work)

I still love you guys

Here is the Answer LOL!!

2178 * 4 = 8712

'a' must be 1 or 2 or else a 5-digit product would be formed.

but 'a' cant be 1 since d * 4 ends in 'a' and so 'a' must be even. so 'a' is 2

d must then be 3 or 8 since 4*d ends in 2. but d cant be 3 because 4*a (plus any carry) equals d so d must be at least 4. so d is 8.

at this point you can just try the other numbers for c and see what b must be. only the one combination works.

(or, if you notice that there is no carry digit with 4*b, (since 2*4=8 already) b must be 0 or 1 (2 is used already), and 0 wont work)

I still love you guys

#7

Ok.

#8

one of the letters equals zero

#9

I thought some people here know more than just Guitar

Here is the Answer LOL!!

2178 * 4 = 8712

'a' must be 1 or 2 or else a 5-digit product would be formed.

but 'a' cant be 1 since d * 4 ends in 'a' and so 'a' must be even. so 'a' is 2

d must then be 3 or 8 since 4*d ends in 2. but d cant be 3 because 4*a (plus any carry) equals d so d must be at least 4. so d is 8.

at this point you can just try the other numbers for c and see what b must be. only the one combination works.

(or, if you notice that there is no carry digit with 4*b, (since 2*4=8 already) b must be 0 or 1 (2 is used already), and 0 wont work)

I still love you guys

So what I thought was right... You should've made it clear that ABC and D were digits, rather than numbers being multiplied together (as they would be in algebra)

#10

So what I thought was right... You should've made it clear that ABC and D were digits, rather than numbers being multiplied together (as they would be in algebra)

Only small letters are used actually, never seen caps used in algebra.