You may have heard this before, but in case you haven't, here is a logic puzzle. I wasn't able to solve this, but my brother was. I know the answer, now:

Person x and y have the following conversation:

x: I forgot how old your three kids are.
y: The product of their ages is 36.
x: I still don't know their ages.
y: The sum of their ages is the same as your house number.
x: I still don't know their ages.
y: The oldest one has red hair.
x: Now I know their ages!

How old are they?

The answer is not some dumb obvious answer. It is possible to find all 3 ages from the information above.
Oh ****, I've seen this before...I have a book of logic riddles in it, and this was the hardest I think...

EDIT: I just cheated and looked it up, and I really don't see how anyone could get that.
What was his house number?
uhhhh, yea
Quote by DarkDude110
What was his house number?
That doesn't matter, if you want to find the answer.
I have no clue.
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Quote by Steve The Plank
2,2,9.

3,2,6..
Its 2, 3 and 6. 2x3=6, 6x6=36. right?
Well, person y knows their ages because he knows his own house number. Since we don't know person y's house number, we have insufficient information.

Steve The Plank was right. It's 2, 2 and 9. Here's why (copied and pasted from somewhere else because I'm lazy):

Like all numbers, 36 can be broken down into primes in only one way: 36 = 2*2*3*3

From this breakdown we can discover the eight possible configurations of the children's ages:

1,1,36
1,2,18
1,3,12
1,4,9
1,6,6
2,2,9
2,3,6
3,3,4

If we look at the sums of the different configurations, we will find:

1+1+36=38
1+2+18=21
1+3+12=16
1+4+9=14
1+6+6=13
2+2+9=13
2+3+6=11
3+3+4=10

Since we know that person y couldn't tell what the children's ages were from the second hint (and since person y no doubt knows his own house number) we can conclude that only two configurations are possible - 1,6,6 and 2,2,9.

From the third clue, we know that there is an oldest child, so the configuration 1,6,6 is impossible.

Therefore, the children's ages are 2, 2 and 9.
Damn, that's a good one.
Quote by Steve The Plank
2,2,9.

i believe steve the plank has it. idk tho...

EDIT:i knew it!
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OMG

eddievh2, you are a genuis, and true man of action

damn right

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or else, how good are you at drawing penises?

lulz
Quote by Malakian88
Well, person y knows their ages because he knows his own house number. Since we don't know person y's house number, we have insufficient information.
You have to read the wording of his statements. Which is why it's called a logic puzzle. I first read this in a book given to me about propositional and systematic logic.

It is possible to figure out.
Well his house number is the same as the total of his kids ages'...
Derp.
i cant solve it.
Yeah, I thought of either 2 2 9 or 2 3 6

I still don't get the house number clue though. I'm kinda high, so my head isn't thinking in a logical perspective at the moment lol.

Steve The Plank was right. It's 2, 2 and 9. Here's why (copied and pasted from somewhere else because I'm lazy):

Like all numbers, 36 can be broken down into primes in only one way: 36 = 2*2*3*3

From this breakdown we can discover the eight possible configurations of the children's ages:

1,1,36
1,2,18
1,3,12
1,4,9
1,6,6
2,2,9
2,3,6
3,3,4

If we look at the sums of the different configurations, we will find:

1+1+36=38
1+2+18=21
1+3+12=16
1+4+9=14
1+6+6=13
2+2+9=13
2+3+6=11
3+3+4=10

Since we know that person y couldn't tell what the children's ages were from the second hint (and since person y no doubt knows his own house number) we can conclude that only two configurations are possible - 1,6,6 and 2,2,9.

From the third clue, we know that there is an oldest child, so the configuration 1,6,6 is impossible.

Therefore, the children's ages are 2, 2 and 9.

Holy crap. That's amazing.
2,2,9
GO YANKEES!
Quote by Archaon
Yeah, I thought of either 2 2 9 or 2 3 6

I still don't get the house number clue though. I'm kinda high, so my head isn't thinking in a logical perspective at the moment lol.

There are two that add up to 13. Had all the sums been unique, x would have been able to solve it at the second clue. But, since he couldn't, then his house number must be 13.