I came across this problem in an optional homework assignment and have little idea of what to do with it...

Could somebody explain to me some of the methods/properties they would use to solve for K to make it a true statement? I don't see how 3 root (a^9b^k) can possibly end up with a to the 3rd. Isn't 3 the square of 9? So confused...
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3 is the square of 9, but consider the fact that K is the same in and out of the radical... that means that whatever happened in taking the cube root of the problem happened to make it come to (A^3)(B^k)
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3 is the square of 9, but consider the fact that K is the same in and out of the radical... that means that whatever happened in taking the cube root of the problem happened to make it come to (A^3)(B^k)

Yea, that crossed my mind. I'm just having trouble thinking of a value that could do that o.o

I guess I'll just go through a list of numbers with strange properties like that... Or something.

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It's optional, who cares.

I chose to do it in the first place because I need to understand the material well enough to perform well on the test. And I don't, as of this moment.
TOO MANY PUPPIES

Soda sucks.

Edit: maybe you weren't looking for that, but that's how powers/roots work.
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Edit: maybe you weren't looking for that, but that's how powers/roots work.

Ah, thank you, that's EXACTLY it. I knew that I had something wrong there. Praise Maus24

EDIT:... So k=0 and 1?
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Soda sucks.
oh, and when you take a exponent to another exponent, you multiply. a.k.a..... (a^3)^3 = a^9

I'd say that's a pretty radical expression!!
to revise my previous post, K would equal 0, not one. (The cubic root of 1 is 1)
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to revise my previous post, K would equal 0, not one. (The cubic root of 1 is 1)

Correct sir is correct
.....k can equal to any value and the equality would be correct....
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.....k can equal to any value and the equality would be correct....

wrong dude is wrong
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wrong dude is wrong