#1


I came across this problem in an optional homework assignment and have little idea of what to do with it...

Could somebody explain to me some of the methods/properties they would use to solve for K to make it a true statement? I don't see how 3 root (a^9b^k) can possibly end up with a to the 3rd. Isn't 3 the square of 9? So confused...
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#2
3 is the square of 9, but consider the fact that K is the same in and out of the radical... that means that whatever happened in taking the cube root of the problem happened to make it come to (A^3)(B^k)
#3
It's optional, who cares.
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#4
Quote by synpet713192
3 is the square of 9, but consider the fact that K is the same in and out of the radical... that means that whatever happened in taking the cube root of the problem happened to make it come to (A^3)(B^k)


Yea, that crossed my mind. I'm just having trouble thinking of a value that could do that o.o

I guess I'll just go through a list of numbers with strange properties like that... Or something.

Quote by Gunpowder
It's optional, who cares.


I chose to do it in the first place because I need to understand the material well enough to perform well on the test. And I don't, as of this moment.
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#5


Edit: maybe you weren't looking for that, but that's how powers/roots work.
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#7
Quote by Maus24


Edit: maybe you weren't looking for that, but that's how powers/roots work.


Ah, thank you, that's EXACTLY it. I knew that I had something wrong there. Praise Maus24

EDIT:... So k=0 and 1?
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#8
oh, and when you take a exponent to another exponent, you multiply. a.k.a..... (a^3)^3 = a^9
#11
Quote by 06CardsChamps
to revise my previous post, K would equal 0, not one. (The cubic root of 1 is 1)

Correct sir is correct
#13
Quote by rock.freak667
.....k can equal to any value and the equality would be correct....

wrong dude is wrong
#14
Quote by synpet713192
wrong dude is wrong


I read it wrong.... my bad....darn my ability to not be able to read properly
#15
Ah, another extremely confusing problem...

( 2^2001 )( 5^1950 )/ 4^27

I'm supposed to be finding the amount of digits in that number.

I'm obviously not supposed to actually calculate the number. I'm pretty sure it's going to end up being 10^something, because that's the only reliable way to get a specific number of zeros, atleast at our level. So... Do I multiply the bases and the exponents, or add, or what? Halp :S
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Last edited by Firequacker at Mar 11, 2008,