Precal... dont answer if you are a dumbass.

(x^6) - 1 .... factor completely
i broke it into (x^3 - 1)(x^3 + 1) using the difference of 2 squares
then into (x - 1)(x^2 + x + 1)(x + 1)(x^2 - x + 1) using difference of 2 cubes twice...
now i am stuck... i dont think it is factored as far as it can go, is it?
Quote by rage__against10
its called parythmitic dumass.

How is that factoring it?
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proudly not an overly proud vegetarian
It can't go furthur man. Id have to sit down and work it out to make sure its correct, but that bottom line can't be factored furthur
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