#1

(For those values of x for which a solution exists), solve the following equation for y:

3 e^(2y−9) = 4x^(4) +7

Solve the following equation for y:

log8(2 y+8) = 3 x2+14 (thats log base 8 before the (2Y+8)

Anddd...........

f(x) = |x−19| , x ≠ 19

--------------

x−19

Limit ->19(left hand)

Limit ->19(right hand)

limit ->19

ANY Help from you smart fellow UGers will be greatly appreciated...

3 e^(2y−9) = 4x^(4) +7

Solve the following equation for y:

log8(2 y+8) = 3 x2+14 (thats log base 8 before the (2Y+8)

Anddd...........

f(x) = |x−19| , x ≠ 19

--------------

x−19

Limit ->19(left hand)

Limit ->19(right hand)

limit ->19

ANY Help from you smart fellow UGers will be greatly appreciated...

#2

Whooooosh !

#3

3 e^(2y−9) = 4x^(4) +7

e^(2y-9) = [(4x^4) + 7]/3

2y - 9 = ln([(4x^4) + 7]/3)

2y = ln([(4x^4) + 7]/3) + 9

y = {ln([(4x^4) + 7]/3) + 9}/2

for the second one, I don't think you typed it right, but basically raise do 8 raised to both sides, then you'll get rid of the log 8. Subtract 8 and divide by 2 and you'll have y.

e^(2y-9) = [(4x^4) + 7]/3

2y - 9 = ln([(4x^4) + 7]/3)

2y = ln([(4x^4) + 7]/3) + 9

y = {ln([(4x^4) + 7]/3) + 9}/2

for the second one, I don't think you typed it right, but basically raise do 8 raised to both sides, then you'll get rid of the log 8. Subtract 8 and divide by 2 and you'll have y.

#4

if you have any other questions try goin to yahoo answers. they usually have pretty good stuff

#5

I got 18% in my calculus test... thats a PHAIL