#1
(For those values of x for which a solution exists), solve the following equation for y:
3 e^(2y−9) = 4x^(4) +7

Solve the following equation for y:
log8(2 y+8) = 3 x2+14 (thats log base 8 before the (2Y+8)


Anddd...........


f(x) = |x−19| , x ≠ 19
--------------
x−19

Limit ->19(left hand)
Limit ->19(right hand)
limit ->19


ANY Help from you smart fellow UGers will be greatly appreciated...
#3
3 e^(2y−9) = 4x^(4) +7
e^(2y-9) = [(4x^4) + 7]/3
2y - 9 = ln([(4x^4) + 7]/3)
2y = ln([(4x^4) + 7]/3) + 9
y = {ln([(4x^4) + 7]/3) + 9}/2


for the second one, I don't think you typed it right, but basically raise do 8 raised to both sides, then you'll get rid of the log 8. Subtract 8 and divide by 2 and you'll have y.
GEAR


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