A car of mass 900kg tows a trailer of mass 600kg by means of a rigid tow bad. The car experiences a resistance of 200N and the trailer a resistance of 600N. If the car engine exerts a forward force of 3KN, find the tension in the tow bar and the acceleration of the system.

I tried treating the whole thing as a particle in order to get the acceleration, which came out at 0.6 ms^-2, but I'm not sure if I should've taken into account the tension in the tow bar before using F=ma for that. Anyway, I have no idea whatsoever how to get the tension in the tow bar, can anyone help me out here please?

Cheers
I'd help if I could but we're not learning tension until tomorrow... Sorry man
^Haha, yeah, therein lies a problem. Cheers anyway
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Nah, think you're on the right lines.

The tension won't have any effect on the overall acceleration, as it's not an external force.

The next stage, I'm fairly sure, is to work out the the force on the car, and then the trailer, using F=ma.

The difference should be the tension.
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A car of mass 900kg tows a trailer of mass 600kg by means of a rigid tow bad. The car experiences a resistance of 200N and the trailer a resistance of 600N. If the car engine exerts a forward force of 3KN, find the tension in the tow bar and the acceleration of the system.

I tried treating the whole thing as a particle in order to get the acceleration, which came out at 0.6 ms^-2, but I'm not sure if I should've taken into account the tension in the tow bar before using F=ma for that. Anyway, I have no idea whatsoever how to get the tension in the tow bar, can anyone help me out here please?

Cheers

F = ma
3000 - 800 = 1500a
2200 = 1500a
2200 / 1500 = a
1.466 ms^-2 = a

F = ma (Force = Tension)
T = 600 x 1.466
T = 880N