#1
I'm working on a lab due tomorrow and don't really get one question:

How many moles of S2O8 are not used if all the I in mixture 3 is completely changed to 2I?

I=iodine (obtained from a .20 M solution of Potassium Iodide)
2(S)8(O)=thiosulfate (obtained from a .10 M solution of Ammonium Peroxydisulfate)


We also had another solution (Sodium Thiosulfate, 2(Na)2(S)3(O).
We mixed the first two solutions togther, then added the third one and started a timer. When the reaction could be seen (the whole mixture turned blue) we stopped the timer and recorded results. So yeah. Kind of confusing, but does anyone know how to do it?
If you think things can't get worse it's probably only because you lack sufficient imagination.
#2
What are the equations for the reactions?
#3
2(i) + 2(s)8(o) -> 2(i) + 2((s)4(o))
If you think things can't get worse it's probably only because you lack sufficient imagination.
#4
Where did the other oxygen atoms go? And by that equation, I is acting as a catalyst, which it doesn't. Is that the correct equation?
#6
Quote by soulflyV
Lulz balance your equation foo'.

Conservation of mass FTW!!!