#1
If you're doing (b+5ax)/x, would your answer be b+5a, or am I skipping something here?

This little fundamental problem is setting me back a bit, and I can't seem to find any answers on the internet.
TOO MANY PUPPIES

Soda sucks.
#3
Quote by Firequacker
If you're doing (b+5ax)/x, would your answer be b+5a, or am I skipping something here?

This little fundamental problem is setting me back a bit, and I can't seem to find any answers on the internet.

i don't know the answer, but i do know that's wrong.
#4
b/x+5a

you divide both terms by x.. the b becomes a fraction. in the 5ax, the x's cancel out
well....sorry
#5
Quote by edawg
b/x+5a

you divide both terms by x.. the b becomes a fraction. in the 5ax, the x's cancel out



Okay, thanks. That was actually the other answer I was thinking it would be...

Anyone dare to tell this man he is wrong? I'd really like a few opinions.
TOO MANY PUPPIES

Soda sucks.
#7
hes dead on
I got my own life to live,
I'm the one that's going to die
when its time for me to die.
So let me live my life
the way i want to.
-Jimi Hendrix, If 6 was 9
#8
hes right because if you divide both terms by x then its initially b/x + 5ax/x and that then simplifies to b/x + 5a
#10
Nirvana guy beat me to it, but yea
its b/x+5a.

i guess the next qustion is,
whos in algerbra 1?
#11
Well, if it gives you any peace of mind just know that you will rarely need to do that kind of stuff when you get into higher math courses because b/x+5a is just as hard to work with as (b+5ax)/x. But I guess you still need to know how to do it.
#14
I ended up with the area between the paraboloid x^2 + z^2 = 1 and the sphere 3(x^2+y^2+z^2) = 27. I must be doing something wrong.
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