#1

how would i solve this?...

(calculus)

A company knows that unit cost C and unit revenue R from the production and sale of x units are related by C= (R^2 / 182,000)+ 8033. Find the rate of change of revenue per unit when the cost per unit is changing by $11 and the revenue is $4000.

(calculus)

A company knows that unit cost C and unit revenue R from the production and sale of x units are related by C= (R^2 / 182,000)+ 8033. Find the rate of change of revenue per unit when the cost per unit is changing by $11 and the revenue is $4000.

#2

i'm taking 10th grade advanced geometry, can't help you, sorry....

#3

yeah, im in 10th grade, so im no help to ya

#4

Can't remember what it's called, opposite of integration

dC/dr = r/364,000

Then do something from there.

Probably... It's been a while since I've done maths.

EDIT: Ok never mind, that's just the rate of change of the cost...

EDIT2: Re-arrange it so 'r' is the subject of the equation, then differentiate it to find an equation for the rate of change of 'C'. After that just plug in some numbers...

dC/dr = r/364,000

Then do something from there.

Probably... It's been a while since I've done maths.

EDIT: Ok never mind, that's just the rate of change of the cost...

EDIT2: Re-arrange it so 'r' is the subject of the equation, then differentiate it to find an equation for the rate of change of 'C'. After that just plug in some numbers...

*Last edited by dangorironhide at Apr 30, 2008,*

#5

I'm not doing your homework for you you cheeky fecker

#6

pie....

everything = pie

everything = pie

#7

dR = (91000*11)/4000 = 250.25, I believe.

#8

how would i solve this?...

(calculus)

A company knows that unit cost C and unit revenue R from the production and sale of x units are related by C= (R^2 / 182,000)+ 8033. Find the rate of change of revenue per unit when the cost per unit is changing by $11 and the revenue is $4000.

I cant help but think you have missed something out

Like where does x exist in the equation?

#9

i think if u differentiate both sides with respect to x...u get

dc/dx=(r/91000)dr/dx

and according to what u wrote (dc/dx)=11 and r=4000..

u do the rest

dc/dx=(r/91000)dr/dx

and according to what u wrote (dc/dx)=11 and r=4000..

u do the rest

#10

dR = (91000*11)/4000 = 250.25, I believe.

where do you get 91000?

#11

182,000/2, because if you are taking the derivative with respect to R, the R^2/182,000 becomes 2R/182,000, or R/91,000

#12

Why is it only ever high school math the pit is stuck at?

Does no one on here have an education?

Does no one on here have an education?

#13

Why is it only ever high school math the pit is stuck at?

Does no one on here have an education?

nope....

#14

Why is it only ever high school math the pit is stuck at?

Does no one on here have an education?

Nah, we have British college Maths too. Any further and people can't help out

Gawd sakes, call it maths, it's like calling physics physic.

#15

are you sure that that is the question word for word???

#16

how would i solve this?...

(calculus)

A company knows that unit cost C and unit revenue R from the production and sale of x units are related by C= (R^2 / 182,000)+ 8033. Find the rate of change of revenue per unit when the cost per unit is changing by $11 and the revenue is $4000.

ok so dc/dx = $11 dc/dr = 91000r

therefore dx/dr = 11/91000r

then dr/dx = 91000r/11 dr/dx being therate of change of the revenue in respec to x(the number of units)

therefore for each individual unit it is 91000r/11/x = 8272.73r/x

im prob full of crap but is that the answer????

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