#1

im stuck on a few problems, can anyone help me out?

1. Gregory wants to build a garden in the shape of an isosceles triangle with one of the congruent sides equal to 12 yards. If the area of his garden will be 55 square yards, find, to the nearest tenth of a degree, the 3 angles of the triangle.

2. Express, in simplest a+bx form, the roots of the equation x^2 +5=4x

1. Gregory wants to build a garden in the shape of an isosceles triangle with one of the congruent sides equal to 12 yards. If the area of his garden will be 55 square yards, find, to the nearest tenth of a degree, the 3 angles of the triangle.

2. Express, in simplest a+bx form, the roots of the equation x^2 +5=4x

#2

π.

#3

1/2abcos@ = area

1/2*12*12cos@ = 55

@=cos^-1 (55 / 72)

other two angles = (360 - @)/2

1/2*12*12cos@ = 55

@=cos^-1 (55 / 72)

other two angles = (360 - @)/2

#4

2. x^2 - 4x + 5 = 0

are you sure that's right? there are complex roots abrewing here.

are you sure that's right? there are complex roots abrewing here.

#5

sweet

thanks

thanks

#6

im stuck on a few problems, can anyone help me out?

1. Gregory wants to build a garden in the shape of an isosceles triangle with one of the congruent sides equal to 12 yards. If the area of his garden will be 55 square yards, find, to the nearest tenth of a degree, the 3 angles of the triangle.

2. Express, in simplest a+bx form, the roots of the equation x^2 +5=4x

1. To lazy to do

2. Factor and set to zero then use the factored () to solve for x (x+1)(x-5)=0 x=-1,5

I do not know what you mean by a+bx, hope this helps though.

#7

Ha Ha you're in school.

#8

1. To lazy to do

2. Factor and set to zero then use the factored () to solve for x (x+1)(x-5)=0 x=-1,5

I do not know what you mean by a+bx, hope this helps though.

doesn't work, (x+1)(x-5) gives x^2-4x-5

you may need the formula