#1

Yeah.

Basically, I'm so confused with ohms that it's not funny!

I have a project in mind, 4x12 cab to replace my crappy cab. It was going to be equipped with 4 celestions, 2 v30's, and 2 G12T-75's.

If all 4 of the speakers are rated at 8 ohms, in a series, what is the total rating?

What about if they were all rated at 16ohms each?

Thanks.

Basically, I'm so confused with ohms that it's not funny!

I have a project in mind, 4x12 cab to replace my crappy cab. It was going to be equipped with 4 celestions, 2 v30's, and 2 G12T-75's.

If all 4 of the speakers are rated at 8 ohms, in a series, what is the total rating?

What about if they were all rated at 16ohms each?

Thanks.

#2

dont quote me on this but i think you retain 8 ohms for the cab

#3

read this, it will answer most questions.

#4

#5

Yeah.

Basically, I'm so confused with ohms that it's not funny!

I have a project in mind, 4x12 cab to replace my crappy cab. It was going to be equipped with 4 celestions, 2 v30's, and 2 G12T-75's.

If all 4 of the speakers are rated at 8 ohms, in a series, what is the total rating?

What about if they were all rated at 16ohms each?

Thanks.

If you put 4 speakers rated at 8 ohms each in series the total resistance will be 32 ohms. If they were 16 ohms each then you would have a total resistance of 64 ohms. I presume you want a total resistance of 8 ohms, which would require wiring pairs of speakers in parallel and then wiring those pairs together in series. I think.

#6

with four 8 ohm speakers you can get 2 ohms, 8 ohms, or 32 ohms. with four 16 ohm speakers you can get 4 ohms, 16 ohms, and 64 ohms. guitar heads usually use 4, 8 or 16 ohms, so you need to see what your head uses. heres what to do in each case:

4 ohms - four 16 ohm speakers in parallel

8 ohms - four 8 ohm speakers in series-parallel (two sets of two in series, with the two sets in parallel)

16 ohms - four 16 ohm speakers in series-parallel

4 ohms - four 16 ohm speakers in parallel

8 ohms - four 8 ohm speakers in series-parallel (two sets of two in series, with the two sets in parallel)

16 ohms - four 16 ohm speakers in series-parallel

#7

Brain.......hurts.....

okay, I understand that you can get 2 ohms with 2 3 ohms speakers but how can you get 4 or 8 ohms?

#8

Ok, the math is pretty simple.

Series speakers (or any impedance or resistance) just adds normally. Two 8's add up to 16. Simple enough.

Parallels are more complicated. In words:

You add up the inverse of each impedance or resistance, and then take the inverse of the result. Ok, in actual math stuff:

Two 8 ohms in parallel - first, add the inverse of each:

(1 / 8) + (1 / 8) = 0.25

Now, take the inverse of the result:

1 / 0.25 = 4 ohms

Now, series/parallel combinations work the same way. For example, two 8's in series which are wired in parallel with two other 8's in series - first, the 8's in series add up to 16 each. Now, two parallel 16's:

(1 / 16) + (1 / 16) = 0.125

Now, take the inverse:

1 / 0.25 = 8 ohms

There will be a quiz at the end of the semester!

Series speakers (or any impedance or resistance) just adds normally. Two 8's add up to 16. Simple enough.

Parallels are more complicated. In words:

You add up the inverse of each impedance or resistance, and then take the inverse of the result. Ok, in actual math stuff:

Two 8 ohms in parallel - first, add the inverse of each:

(1 / 8) + (1 / 8) = 0.25

Now, take the inverse of the result:

1 / 0.25 = 4 ohms

Now, series/parallel combinations work the same way. For example, two 8's in series which are wired in parallel with two other 8's in series - first, the 8's in series add up to 16 each. Now, two parallel 16's:

(1 / 16) + (1 / 16) = 0.125

Now, take the inverse:

1 / 0.25 = 8 ohms

There will be a quiz at the end of the semester!

#9