#1
Can someone help me with this problem
we did it a long time ago and my final is coming up and i forgot how to do it

sec x = 2.102
#2
Well what are we supposed to be looking for and solving?
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#6
solve for theta (x)

i know how to do sin x = whatever
You do sin^-1 and then the number
but i dont know how to do sec, i keep getting errors
#7
in your calculator type in 1/cos^-1(2.102)

cos^1 is the arccos and your calculatr will give you the angle measure.
you put it all under one because sec= 1/cos
#8
jus solve for cos x = 1/2.102

as in x = arccos(1/2.102)

(arccos is cos to the minus 1 if u didnt know)
#9
secx = 1\cos x
so 1\cosx =2.102
1 = 2.102 cos x
1/2.102 = cos x
take the cos inverse or cos -1 of each side
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#11
Quote by riffmasterjosh
secx = 1\cos x
so 1\cosx =2.102
1 = 2.102 cos x
1/2.102 = cos x
take the cos inverse or cos -1 of each side


thanks that helped
#12
Quote by I Am Jack!
sec x = 2.102
/c
sex = 2.102 /c

sex = 69

2.102/c = 69

c = 0.0305 (roughly)

sex = 69