Can someone help me with this problem
we did it a long time ago and my final is coming up and i forgot how to do it

sec x = 2.102
Well what are we supposed to be looking for and solving?
Quote by nightraven
can't stand public showers
and yes i do have a small penis

Quote by thewho182
people in public showers make fun of my big dick

Quote by kyle33093
i would if pee pee was bigger

sec = 1/cos, that's about all I can remember sorry.
post the full question then i should be able to help

solve for theta (x)

i know how to do sin x = whatever
You do sin^-1 and then the number
but i dont know how to do sec, i keep getting errors
in your calculator type in 1/cos^-1(2.102)

cos^1 is the arccos and your calculatr will give you the angle measure.
you put it all under one because sec= 1/cos
jus solve for cos x = 1/2.102

as in x = arccos(1/2.102)

(arccos is cos to the minus 1 if u didnt know)
secx = 1\cos x
so 1\cosx =2.102
1 = 2.102 cos x
1/2.102 = cos x
take the cos inverse or cos -1 of each side
Deacon of Zeppelinism PM TheHeartbreaker to join
speed demon of the UG Jeepers
Member of the Neutral Milk Hotel club PM Hamish5178 to join~
sec x = 2.102
/c
sex = 2.102 /c

sex = 69

2.102/c = 69

c = 0.0305 (roughly)
rawr
Quote by riffmasterjosh
secx = 1\cos x
so 1\cosx =2.102
1 = 2.102 cos x
1/2.102 = cos x
take the cos inverse or cos -1 of each side

thanks that helped
Quote by I Am Jack!
sec x = 2.102
/c
sex = 2.102 /c

sex = 69

2.102/c = 69

c = 0.0305 (roughly)

sex = 69