#1
so i need help with math

f(x)= sin * x
f'(x) would be
f'(x)= sin
right?


but i dont know what would be the next step ....



i drawed the second one how it could look like
the first one was given
Quote by frankv
Tokio Hotel is probably the worst thing Germany has produced since WW2.


#2
Quote by Toast1337
so i need help with math


No, do your own homework.
Quote by nightraven
can't stand public showers
and yes i do have a small penis



Quote by thewho182
people in public showers make fun of my big dick


Quote by kyle33093
i would if pee pee was bigger


#4
Wouldn't sin= f(x)/x then?
Newbs are dorks... oh wait, I'm a newb... shoot...


I DRINK YOUR MILKSHAKE!!!!!! I DRINK IT UP!!!

One of these smilies is mentally challenged
#6
if f(x) = sin x, f'(x) = cos x

f' means first differential of.

Now, do you own homework, surely you can draw a graph of y = cosx.
Quote by Felkara
Dude, you just made the most intelligent post in this entire thread. Congrats.
#7
Draw a penis and swear by it to your teacher that its the right answer
people with large sig's are clearly compensating for something.
#8
The differential of Sinx is cosx

Therefore;

f (x) = sinx
f ' (x) = cosx

So the gradient of the graph of sinx is cosx. Now I'm sure you can draw that right
I hope it doesn't seem, like I'm young, foolish, and green.
Let me in for a minute, you're not my life but I want you in it


O Dayya, te echaré de menos, siempre

Y siempre
Y para siempre
#9
if you mean
f(x)= sin(x)
f'(x)= cos(x)

of if you mean

f(x)= x sin(x)
f'(x)= xcos(x) + sin(x)
#10
Yea, cos (x) would be the first order differential

Graph of cos (x) is super friggin easy


The Game, you lost it
#11
im assuming you are trying to find the derivative of f(x) but u have to know the correct ones. trig functions dont work like normal ones. they have their own properties, for this one the derivative would be cos x. u cant have sin of nothing
#13
thx to all
Quote by frankv
Tokio Hotel is probably the worst thing Germany has produced since WW2.


#14
Die Ableitung der Sinusfunktion ist der Cosinus
[img]http://img300.imageshack.us/img300/3760/356h356h365pc1.png[/img]
Die Ruhe vor dem Sturm.
#15
so for the first one it would be
f'(-pi)=cos(-pi)=0.99??
Quote by frankv
Tokio Hotel is probably the worst thing Germany has produced since WW2.


#16
i dont get it
i only need an example for -Pi
Quote by frankv
Tokio Hotel is probably the worst thing Germany has produced since WW2.


#17
yeah umm

this is why i'm majoring in buying a bus and roaming around with my guitar.....

Yeah. The rumors are true. I'm a twat.
#19
X is the y differential with regards to the 3pt unit in the y axis when x(ycos)^2/E=Mc^2x44.3576

therefore, X is like Y except its X and not Y lolwtf
Epiphone: Les paul Custom SB
Line Six Spider III 15
70$ wal-mart brand acoustic

Quote by black amendment
You're awesome, dude.
#20
Dude, you've got some stuff seriously wrong. Sin is an operator, not something you multiply by, so you cannot simply have
f'(x) = sin
as this is meaningless. I suggest reading up on functions and operators before attempting to perform calculus with them. Or you can simply learn the relationships by heart.
#21
Sine is a function of some variable. You don't have "sin" by itself...
Quote by denizenz
I'll logic you right in the thyroid.

Art & Lutherie
#22
The gradient of Sinx is Cosx

So at the point where x = pi;


Sin pi = whatever
thereofre the gradient at the point (pi, 0) is cos pi = 1
I hope it doesn't seem, like I'm young, foolish, and green.
Let me in for a minute, you're not my life but I want you in it


O Dayya, te echaré de menos, siempre

Y siempre
Y para siempre
#23
sin (pi) = 0...
look at a unit circle it has all the exact answers on it
#25
Do what everyone did in my school.. See this question and yell at the teacher about how we'll never use this in life.
#26
Quote by Pricycle
sin (pi) = 0...
look at a unit circle it has all the exact answers on it

Yes this is the correct answer.

(Just putting it all in one place)

f(x) = sin x

f'(x) = cos x


substituting in pi for x in

f'(x) = cos x

f'(pi) = cos (Pi)

f'(pi) = 0.


EDIT: Also, in your first post you have "sin * x". Please remember that it is "sin x", not sin times x, or you will get marked down. Speaking from experience here.
Last edited by soulflyV at Jun 11, 2008,
#27
Quote by Pricycle
sin (pi) = 0...
look at a unit circle it has all the exact answers on it


oh man that sounds so sexy! haha

you smart head of a kid..
Sig.



After "bio class" did you and your classmates organize a "Celebrity Skateboard Tournament" to save your beloved "Rec Center" where "Coach Anderson" taught you how to become men?
#28
Quote by BlackLuster
The differential of Sinx is cosx

Therefore;

f (x) = sinx
f ' (x) = cosx

So the gradient of the graph of sinx is cosx. Now I'm sure you can draw that right


this