#1

so i need help with math

f(x)= sin * x

f'(x) would be

f'(x)= sin

right?

but i dont know what would be the next step ....

i drawed the second one how it could look like

the first one was given

f(x)= sin * x

f'(x) would be

f'(x)= sin

right?

but i dont know what would be the next step ....

i drawed the second one how it could look like

the first one was given

#2

so i need help with math

No, do your own homework.

#3

No, do your own homework.

This.

#4

Wouldn't sin= f(x)/x then?

#5

i dropped out before this **** was introduced to me

#6

if f(x) = sin x, f'(x) = cos x

f' means first differential of.

Now, do you own homework, surely you can draw a graph of y = cosx.

f' means first differential of.

Now, do you own homework, surely you can draw a graph of y = cosx.

#7

Draw a penis and swear by it to your teacher that its the right answer

#8

The differential of Sinx is cosx

Therefore;

f (x) = sinx

f ' (x) = cosx

So the gradient of the graph of sinx is cosx. Now I'm sure you can draw that right

Therefore;

f (x) = sinx

f ' (x) = cosx

So the gradient of the graph of sinx is cosx. Now I'm sure you can draw that right

#9

if you mean

f(x)= sin(x)

f'(x)= cos(x)

of if you mean

f(x)= x sin(x)

f'(x)= xcos(x) + sin(x)

f(x)= sin(x)

f'(x)= cos(x)

of if you mean

f(x)= x sin(x)

f'(x)= xcos(x) + sin(x)

#10

Yea, cos (x) would be the first order differential

Graph of cos (x) is super friggin easy

The Game, you lost it

Graph of cos (x) is super friggin easy

The Game, you lost it

#11

im assuming you are trying to find the derivative of f(x) but u have to know the correct ones. trig functions dont work like normal ones. they have their own properties, for this one the derivative would be cos x. u cant have sin of nothing

#12

phuck math

#13

thx to all

#14

Die Ableitung der Sinusfunktion ist der Cosinus

#15

so for the first one it would be

f'(-pi)=cos(-pi)=0.99??

f'(-pi)=cos(-pi)=0.99??

#16

i dont get it

i only need an example for -Pi

i only need an example for -Pi

#17

yeah umm

this is why i'm majoring in buying a bus and roaming around with my guitar.....

this is why i'm majoring in buying a bus and roaming around with my guitar.....

#18

phuck math

+1

#19

X is the y differential with regards to the 3pt unit in the y axis when x(ycos)^2/E=Mc^2x44.3576

therefore, X is like Y except its X and not Y lolwtf

therefore, X is like Y except its X and not Y lolwtf

#20

Dude, you've got some stuff seriously wrong. Sin is an operator, not something you multiply by, so you cannot simply have

f'(x) = sin

as this is meaningless. I suggest reading up on functions and operators before attempting to perform calculus with them. Or you can simply learn the relationships by heart.

f'(x) = sin

as this is meaningless. I suggest reading up on functions and operators before attempting to perform calculus with them. Or you can simply learn the relationships by heart.

#21

Sine is a function of some variable. You don't have "sin" by itself...

#22

The gradient of Sinx is Cosx

So at the point where x = pi;

Sin pi = whatever

thereofre the gradient at the point (pi, 0) is cos pi = 1

So at the point where x = pi;

Sin pi = whatever

thereofre the gradient at the point (pi, 0) is cos pi = 1

#23

sin (pi) = 0...

look at a unit circle it has all the exact answers on it

look at a unit circle it has all the exact answers on it

#24

Holy crap are you guys are smart...now I feel retarded.

#25

Do what everyone did in my school.. See this question and yell at the teacher about how we'll never use this in life.

#26

sin (pi) = 0...

look at a unit circle it has all the exact answers on it

Yes this is the correct answer.

(Just putting it all in one place)

f(x) = sin x

f'(x) = cos x

substituting in pi for x in

f'(x) = cos x

f'(pi) = cos (Pi)

f'(pi) = 0.

EDIT: Also, in your first post you have "sin * x". Please remember that it is "sin x", not sin times x, or you will get marked down. Speaking from experience here.

*Last edited by soulflyV at Jun 11, 2008,*

#27

sin (pi) = 0...

look at a unit circle it has all the exact answers on it

oh man that sounds so sexy! haha

you smart head of a kid..

#28

The differential of Sinx is cosx

Therefore;

f (x) = sinx

f ' (x) = cosx

So the gradient of the graph of sinx is cosx. Now I'm sure you can draw that right

this