so i need help with math

f(x)= sin * x
f'(x) would be
f'(x)= sin
right?

but i dont know what would be the next step ....

i drawed the second one how it could look like
the first one was given
Quote by frankv
Tokio Hotel is probably the worst thing Germany has produced since WW2.

Quote by Toast1337
so i need help with math

Quote by nightraven
can't stand public showers
and yes i do have a small penis

Quote by thewho182
people in public showers make fun of my big dick

Quote by kyle33093
i would if pee pee was bigger

Quote by Neillya1

This.
SEX!

Now I have your attention, witness the awesomeness that is my sig
__________________

Quote by GuitarManDan15
win

__________________

Free Dean V To Loving Home
Wouldn't sin= f(x)/x then?
Newbs are dorks... oh wait, I'm a newb... shoot...

I DRINK YOUR MILKSHAKE!!!!!! I DRINK IT UP!!!

One of these smilies is mentally challenged
i dropped out before this **** was introduced to me
HiMyNameIsMatt
if f(x) = sin x, f'(x) = cos x

f' means first differential of.

Now, do you own homework, surely you can draw a graph of y = cosx.
Quote by Felkara
Dude, you just made the most intelligent post in this entire thread. Congrats.
Draw a penis and swear by it to your teacher that its the right answer
people with large sig's are clearly compensating for something.
The differential of Sinx is cosx

Therefore;

f (x) = sinx
f ' (x) = cosx

So the gradient of the graph of sinx is cosx. Now I'm sure you can draw that right
I hope it doesn't seem, like I'm young, foolish, and green.
Let me in for a minute, you're not my life but I want you in it

O Dayya, te echaré de menos, siempre

Y siempre
Y para siempre
if you mean
f(x)= sin(x)
f'(x)= cos(x)

of if you mean

f(x)= x sin(x)
f'(x)= xcos(x) + sin(x)
Yea, cos (x) would be the first order differential

Graph of cos (x) is super friggin easy

The Game, you lost it
im assuming you are trying to find the derivative of f(x) but u have to know the correct ones. trig functions dont work like normal ones. they have their own properties, for this one the derivative would be cos x. u cant have sin of nothing
thx to all
Quote by frankv
Tokio Hotel is probably the worst thing Germany has produced since WW2.

Die Ableitung der Sinusfunktion ist der Cosinus
[img]http://img300.imageshack.us/img300/3760/356h356h365pc1.png[/img]
Die Ruhe vor dem Sturm.
so for the first one it would be
f'(-pi)=cos(-pi)=0.99??
Quote by frankv
Tokio Hotel is probably the worst thing Germany has produced since WW2.

i dont get it
i only need an example for -Pi
Quote by frankv
Tokio Hotel is probably the worst thing Germany has produced since WW2.

yeah umm

this is why i'm majoring in buying a bus and roaming around with my guitar.....

Yeah. The rumors are true. I'm a twat.
Quote by HerVoiCeResIdEs
phuck math

+1
HiMyNameIsMatt
X is the y differential with regards to the 3pt unit in the y axis when x(ycos)^2/E=Mc^2x44.3576

therefore, X is like Y except its X and not Y lolwtf
Epiphone: Les paul Custom SB
Line Six Spider III 15
70\$ wal-mart brand acoustic

Quote by black amendment
You're awesome, dude.
Dude, you've got some stuff seriously wrong. Sin is an operator, not something you multiply by, so you cannot simply have
f'(x) = sin
as this is meaningless. I suggest reading up on functions and operators before attempting to perform calculus with them. Or you can simply learn the relationships by heart.
Sine is a function of some variable. You don't have "sin" by itself...
Quote by denizenz
I'll logic you right in the thyroid.

Art & Lutherie
The gradient of Sinx is Cosx

So at the point where x = pi;

Sin pi = whatever
thereofre the gradient at the point (pi, 0) is cos pi = 1
I hope it doesn't seem, like I'm young, foolish, and green.
Let me in for a minute, you're not my life but I want you in it

O Dayya, te echaré de menos, siempre

Y siempre
Y para siempre
sin (pi) = 0...
look at a unit circle it has all the exact answers on it
Holy crap are you guys are smart...now I feel retarded.
Do what everyone did in my school.. See this question and yell at the teacher about how we'll never use this in life.
Quote by Pricycle
sin (pi) = 0...
look at a unit circle it has all the exact answers on it

Yes this is the correct answer.

(Just putting it all in one place)

f(x) = sin x

f'(x) = cos x

substituting in pi for x in

f'(x) = cos x

f'(pi) = cos (Pi)

f'(pi) = 0.

EDIT: Also, in your first post you have "sin * x". Please remember that it is "sin x", not sin times x, or you will get marked down. Speaking from experience here.
Last edited by soulflyV at Jun 11, 2008,
Quote by Pricycle
sin (pi) = 0...
look at a unit circle it has all the exact answers on it

oh man that sounds so sexy! haha

you smart head of a kid..
Sig.

After "bio class" did you and your classmates organize a "Celebrity Skateboard Tournament" to save your beloved "Rec Center" where "Coach Anderson" taught you how to become men?
Quote by BlackLuster
The differential of Sinx is cosx

Therefore;

f (x) = sinx
f ' (x) = cosx

So the gradient of the graph of sinx is cosx. Now I'm sure you can draw that right

this