#1

i have some natural log problems with the directions "simplify":

1. 1/2ln9+ ln12 - 2ln3

i plug this into my graphing calculator and get:

3.381227841

is that the answer? or do i raise the e to that so that: e^(3.381227841)=4

which is the answer?

thanks so much, my final is tomorrow and i dont know how to do that

1. 1/2ln9+ ln12 - 2ln3

i plug this into my graphing calculator and get:

3.381227841

is that the answer? or do i raise the e to that so that: e^(3.381227841)=4

which is the answer?

thanks so much, my final is tomorrow and i dont know how to do that

*Last edited by axeslinger01 at Jun 9, 2008,*

#2

Its 5.666666666666666666

#3

Its 5.666666666666666666

is that for real?

#4

Nope.

#5

I think it's asking you to condense (I think that's the correct term, correct me if I'm wrong.)

#6

I don't understand, just plug in ln12-ln3 and that's the answer.

Edit: I mean I don't understand why your calculator would not give you the answer if you plugged it in correctly.

Edit: I mean I don't understand why your calculator would not give you the answer if you plugged it in correctly.

#7

My random answer of the day:

or maybe (Ln 9^1/2)(ln 12) / (ln 3^2)=

ln 108^1/2 / ln 3^2.

**1.38629436**or maybe (Ln 9^1/2)(ln 12) / (ln 3^2)=

ln 108^1/2 / ln 3^2.

*Last edited by Ticket48 at Jun 9, 2008,*

#8

IIRC, something like this:

ln4

Correct me if I'm wrong, it's been awhile.

1/2ln9+ ln12 - 2ln3

ln9^(1/2)+ln12 - ln3^(2)

ln3+ln12 - ln 9

ln (36/9)

ln4

ln4

Correct me if I'm wrong, it's been awhile.

1/2ln9+ ln12 - 2ln3

ln9^(1/2)+ln12 - ln3^(2)

ln3+ln12 - ln 9

ln (36/9)

ln4

#9

the answer is ln4 you have to condense it

1/2ln9 is the same as ln 3

ln12 is ln12

2ln3 is the same as ln 9

addeition in logs can be seen as multiplying and subtraction as division

therefore 1/2ln9 + ln12 - 2ln3 is ln(12x3/9) or ln4

1/2ln9 is the same as ln 3

ln12 is ln12

2ln3 is the same as ln 9

addeition in logs can be seen as multiplying and subtraction as division

therefore 1/2ln9 + ln12 - 2ln3 is ln(12x3/9) or ln4

#10

My random answer of the day: 1.38629436

+1

#11

the answer is ln4 you have to condense it

1/2ln9 is the same as ln 3

ln12 is ln12

2ln3 is the same as ln 9

addeition in logs can be seen as multiplying and subtraction as division

therefore 1/2ln9 + ln12 - 2ln3 is ln(12x3/9) or ln4

truth right here...

#12

simplify means your supposed to come up with a new way of saying it... in otherwords combine all the ln's into 1 ln... not solve it...

in other words using simpler explanation... even if they told you x = 2 the simplify of 2x + 4x - 1 x = 5x

in other words using simpler explanation... even if they told you x = 2 the simplify of 2x + 4x - 1 x = 5x

#13

You're wrong. 1/2ln9 = ln3

ln3-2ln3= -ln3 Therefore,

ln12- ln3= whatever the calculator says, I don't know where my Ti 84 is at right now.

ln3-2ln3= -ln3 Therefore,

ln12- ln3= whatever the calculator says, I don't know where my Ti 84 is at right now.

#14

the answer is ln4 you have to condense it

1/2ln9 is the same as ln 3

ln12 is ln12

2ln3 is the same as ln 9

addeition in logs can be seen as multiplying and subtraction as division

therefore 1/2ln9 + ln12 - 2ln3 is ln(12x3/9) or ln4

dude thank you soooo much, i have a final in this **** tomorrow and i'm pulling my hair out. i went back and did the review page and got it right thanks to you

#15

truth right here...

yeah. simplifying means write it in simplest terms. besides, scientifically speaking, an answer should never be approximated. write it in algebraic terms or in root form...

EDIT:i posted something worth a damn

#16

You're wrong. 1/2ln9 = ln3

ln3-2ln3= -ln3 Therefore,

ln12- ln3= whatever the calculator says, I don't know where my Ti 84 is at right now.

While 1/2ln9 does equal 3, the rest of what you said doesn't work. ln3-2ln3 does NOT equal -ln3. Logs don't work that way. 2ln3 is equivalent to ln3^2 or ln9 and -(1)ln3 would be ln(1/3). See above, the answer is ln4.

Also, ln 3- 2ln3 (ln9, see above.) is done wrong anyway. Subtraction between logs is division, ie, ln(3/9).

*Last edited by synopsize at Jun 9, 2008,*

#17

While 1/2ln9 does equal 3

I feel stupid cause I typed that into google and it came out differently. Anyone know why?

#18

I feel stupid cause I typed that into google and it came out differently. Anyone know why?

It probably sees ln as two variables. Not the natural log of something.

Edit: Nevermind. Did you use parentheses? I checked Google and it said you have to use parentheses when asking it to evaluate logs.

*Last edited by Burdell at Jun 9, 2008,*

#19

I believe the answers 3.14

But I failed math 3 years in a row.

But I failed math 3 years in a row.

#20

i failed algerbra 2.......math is for chumps

#21

I feel stupid cause I typed that into google and it came out differently. Anyone know why?

(for some reason I'm really enjoying math tonight.)

It reads it as (1/2) * ln9 instead of (1/2)ln9. Meaning that it solves ln9 (ln9 being an exponent [e^x=9], which comes before multiplication in the order of operations) instead of simplifying the equation to ln9^(1/2) (ln3)

EDIT: Oops, mixed up 9s and 3s.

*Last edited by synopsize at Jun 9, 2008,*

#22

(for some reason I'm really enjoying math tonight.)

It reads it as (1/2) * ln9 instead of (1/2)ln9. Meaning that it solves ln9 (ln9 being an exponent, which comes before multiplication in the order of operations) instead of simplifying the equation to ln9^(1/2) (ln3)

EDIT: Oops, mixed up 9s and 3s.

Dang, that messed me up quite a bit. arg. Well, thanks for the explination.