#2
cant help im taking algebra 1b over again next year....
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#3
Quote by brooklynsoulja1
cant help im taking algebra 1b over again next year....


Fail.
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#4
Quote by Jako215
can somebody help me with this

Solve the equation
x over x2 - 25 + 8 over x - 5 = 4 over x + 5

I cant solve it


Your "over" notation doesn't work for indicating the level of division. Use parentheses and backslashes.
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#8
trying making all the denominators equal, so you can strike them out.
#9
lmao i got the answer 92...wait no
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#10
x^2 - 25 factors out to x + 5 and x - 5. Multiply 8/x-5 by (x+5)/(x+5) and multiply 4/x+5 by (x-5)/(x-5). Then everything has a common denominator, so you can get rid of the denominators and just solve for x through the numerator.
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#11
Quote by darkstar2466
x^2 - 25 factors out to x + 5 and x - 5. Multiply 8/x-5 by (x+5)/(x+5) and multiply 4/x+5 by (x-5)/(x-5). Then everything has a common denominator, so you can get rid of the denominators and just solve for x through the numerator.



thank you Darkstar you just saved me from failing Algebra 2 for the year!!!

the answer s x=-5
#12
Quote by Jako215
thank you Darkstar you just saved me from failing Algebra 2 for the year!!!

the answer s x=-5

Not quite. -5 would make the denominator of the expression on the right equal to 0, and division by zero is undefined.
#13
i got x = -12

x/x(sq)-25 + 8/(x-5) = 4/(x+5)
x/(x-5)(x+5) + 8/(x-5) = 4/(x+5)
divide all by (x-5)(x+5)
x + 8x +40 =4x -20
5x= -60
x = -12
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Last edited by manic at Jun 12, 2008,
#14
nope, cause I'm out of school now.
I can honestly say I have really been far even as decided to use even go want to do look more like.


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