can somebody help me with this

Solve the equation
x over x2 - 25 + 8 over x - 5 = 4 over x + 5

I cant solve it
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cant help im taking algebra 1b over again next year....

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cant help im taking algebra 1b over again next year....

Fail.
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can somebody help me with this

Solve the equation
x over x2 - 25 + 8 over x - 5 = 4 over x + 5

I cant solve it

Your "over" notation doesn't work for indicating the level of division. Use parentheses and backslashes.
Quote by denizenz
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x/x2-25 + 8/x-5 = 4/x+5

is that better

the awnsers are 5 -5 -12 -12 and -5

I plugged in -5 but im not sure if its right
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by "x2" do you mean "2x"?
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by "x2" do you mean "2x"?

no x squared
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trying making all the denominators equal, so you can strike them out.
lmao i got the answer 92...wait no

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x^2 - 25 factors out to x + 5 and x - 5. Multiply 8/x-5 by (x+5)/(x+5) and multiply 4/x+5 by (x-5)/(x-5). Then everything has a common denominator, so you can get rid of the denominators and just solve for x through the numerator.
Quote by denizenz
I'll logic you right in the thyroid.

Art & Lutherie
Quote by darkstar2466
x^2 - 25 factors out to x + 5 and x - 5. Multiply 8/x-5 by (x+5)/(x+5) and multiply 4/x+5 by (x-5)/(x-5). Then everything has a common denominator, so you can get rid of the denominators and just solve for x through the numerator.

thank you Darkstar you just saved me from failing Algebra 2 for the year!!!

the answer s x=-5
TEN YEARS MAN!

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Quote by Jako215
thank you Darkstar you just saved me from failing Algebra 2 for the year!!!

the answer s x=-5

Not quite. -5 would make the denominator of the expression on the right equal to 0, and division by zero is undefined.
i got x = -12

x/x(sq)-25 + 8/(x-5) = 4/(x+5)
x/(x-5)(x+5) + 8/(x-5) = 4/(x+5)
divide all by (x-5)(x+5)
x + 8x +40 =4x -20
5x= -60
x = -12
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Last edited by manic at Jun 12, 2008,
nope, cause I'm out of school now.
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