#1

im kinda stuck on my math work for the summer and i might be needing some help currently im stuck on this:

simplify the expression:

7*a^5*b^3

^means to the power of

*means times

simplify the expression:

7*a^5*b^3

^means to the power of

*means times

#2

7*(a^2b)^3

#3

mind telling me how you go to that conclusion?

#4

Do your own homework.

#5

Well when you multiply powers, you add the number of the powers together.

3 is the biggest number you can take out of either power.

3 is the biggest number you can take out of either power.

#6

wow, I can't remember math

If simplify means what I think it means I just get 7a^5b^3

EDIT: reading that over, hard to read.

7 a^5 b^3

all in one line, how I had it before looked like it was a to the power of "5b"

If simplify means what I think it means I just get 7a^5b^3

EDIT: reading that over, hard to read.

7 a^5 b^3

all in one line, how I had it before looked like it was a to the power of "5b"

*Last edited by pepsi_lovr at Jul 20, 2008,*

#7

why do you have hw over the summer?

#8

wow, I can't remember math

If simplify means what I think it means I just get 7a^5b^3

If by simplify, you mean "do absolutely nothing to".

#9

cuz im still in high school >.< and this is the usa double >.< >.<

#10

Well when you multiply powers, you add the number of the powers together.

3 is the biggest number you can take out of either power.

but their terms are not the same one is a and the other is b...how can you multiply/add/subtract/divide thouse?!

#11

cuz im still in high school >.< and this is the usa double >.< >.<

Sorry for my lack of American school systems what's usa double?

#12

If by simplify, you mean "do absolutely nothing to".

In this case you don't do anything. The TS must be in a lower level math course.

Go here and try out this... equation? (I dunno what to call it) it comes out with the same answer I came out with.

(7)(a^5)(b^3) is how I'm reading the question.

Simplify means go as far as you can doesn't it? Express in simplest terms.

So: 7(a^5) = 7a^5

7a^5(b^3) = 7 a^5 b^3

EDIT: right forgot to put website ^.^ http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=algebra&s2=simplify&s3=basic

#13

when you raise a power to a power you multiply it by the exponent

#14

Sorry for my lack of American school systems what's usa double?

i meant >.< as i was annoyed at the fact im an american citizen

#15

yes im in a lower math (pre calc 11th grade)

#16

when you raise a power to a power you multiply it by the exponent

But they have different bases, so he's not raising a power to a power. The answer is 7a^5b^3, as someoe said earlier.

#17

how do i solve √6+2√6 it seems i forgot how to do basic math over the summer gonna have to brush up on my skills

yes we've already come to the conclusion that my first question is already simplified i had a feeling it was

yes we've already come to the conclusion that my first question is already simplified i had a feeling it was

#18

but their terms are not the same one is a and the other is b...how can you multiply/add/subtract/divide thouse?!

Well "a" is a number, and so is "b", we just don't know their values.

I think the equation looks something like this:

So it essentially looks like this:

Then you take out the common factor, which is 1^3.

EDIT:

how do i solve √6+2√6 it seems i forgot how to do basic math over the summer gonna have to brush up on my skills

yes we've already come to the conclusion that my first question is already simplified i had a feeling it was

Correct me if I'm wrong, but I think that would be 3√6.

#19

hmm idk soulfly...oh well just drop it, its only one question out of 100...

#20

√6+2√6:

1. Square Whole Problem

2. End up with 6+4*6

3. Basic Grade-School Maths

Unless i'm looking at what you have to do wrong, anytime you don't have a variable in a problem with square roots, you can square the problem to get back to the original number, then finish off the problem. Learn to reverse engineer your answers. That helps too.

1. Square Whole Problem

2. End up with 6+4*6

3. Basic Grade-School Maths

Unless i'm looking at what you have to do wrong, anytime you don't have a variable in a problem with square roots, you can square the problem to get back to the original number, then finish off the problem. Learn to reverse engineer your answers. That helps too.

#21

Haha, I think I'm wrong, actually.

:s

:s

#22

Haha, I think I'm wrong, actually.

:s

when they are separated by parentheses, the exponents get multiplied, not added, so yea, you're wrong (sorry to be so blunt haha)

if it was b^6 then you'd be right though.

#23

guys another problem has stumped me:

5x+15

--------

5x-15

oh and √6+2√6 would equal 3√6 right? i mean why not?

5x+15

--------

5x-15

oh and √6+2√6 would equal 3√6 right? i mean why not?

#24

when they are separated by parentheses, the exponents get multiplied, not added, so yea, you're wrong (sorry to be so blunt haha)

if it was b^6 then you'd be right though.

Ahhh of course. It's been a while.

#25

guys another problem has stumped me:

5x+15

--------

5x-15

oh and √6+2√6 would equal 3√6 right? i mean why not?

3√6 is right

as for the other one, just factor out a 5 from the entire fraction.

#26

im kinda stuck on my math work for the summer and i might be needing some help currently im stuck on this:

simplify the expression:

7*a^5*b^3

^means to the power of

*means times

7ab^8

k

#27

7ab^8

k

No..you can't multiply the exponents of a and b together because they have different bases.

..right?