#1

x = .99999999...

Multiply by 10

10x = 9.9999999...

subtract X

10x - x = 9.9999999... - .9999999...

Simplify

9x = 9

Simplify

x = 1

.333... = 1/3

3 x .333... = 3 x 1/3

.999... = 3/3

.999... = 1

.111... = 1/9

9 x .111... = 9 x 1/9

.999... = 9/9

.999... = 1

1 = 9/9

9/9 = 9 x 1/9

9 x .111... = .999...

thus 1 = .999...

More equations proving this here.

.999999.... = 1

Discuss.

Multiply by 10

10x = 9.9999999...

subtract X

10x - x = 9.9999999... - .9999999...

Simplify

9x = 9

Simplify

x = 1

.333... = 1/3

3 x .333... = 3 x 1/3

.999... = 3/3

.999... = 1

.111... = 1/9

9 x .111... = 9 x 1/9

.999... = 9/9

.999... = 1

1 = 9/9

9/9 = 9 x 1/9

9 x .111... = .999...

thus 1 = .999...

More equations proving this here.

.999999.... = 1

Discuss.

*Last edited by RPGoof at Aug 6, 2008,*

#2

No it doesn't?

#3

0/0=1, which means you can divide by zero.

OMGWTFHAX

OMGWTFHAX

#4

yo dawg, is dis shyt legit? wer tha bitches at yo?

#5

I remember a giant thread on this. This a last year stuff. Don't bring it up again. Get 'outta here, kid.

*pats on back*

*pats on back*

#6

It's a waste of time because you're starting with the answer. Usually if you have a variable you're trying to find it's value. It's a nifty trick, but completely useless.

#7

x = .99999999...

Multiply by 10

10x = 9.9999999...

subtract X10x - x = 9.9999999... - .9999999...

Simplify

9x = 9

Simplify

x = 1

.99999... = 1

Discuss.

You're supposed to subtract X from BOTH sides. So no, it doesn't.

#8

yeah there are so many loopholes in math

whateves, no big deal

whateves, no big deal

#9

But like... it doesn't.

#10

#11

You're supposed to subtract X from BOTH sides. So no, it doesn't.

but x= .999999.... so it doesn't really matter what value you use. They are both interchangeable.

#12

You're supposed to subtract X from BOTH sides. So no, it doesn't.

x = .99999...

so it does work

CHECK YOUR MATH

(sorry for the double post)

#13

You're supposed to subtract X from BOTH sides. So no, it doesn't.

owned.

EDIT: Nevermind.

#14

You're supposed to subtract X from BOTH sides. So no, it doesn't.

You start with x defined as what he has on the right side, so that's legit.

#15

Um, No.

#16

0/0=1, which means you can divide by zero.

OMGWTFHAX

if you think about 0/0 can = any number

cause 2 X 0 = 0 so there for 0/0 should = 2

#17

this is the same as 1/3=.333333... so 3/3=.9999999

just kinda rounds.. dunno

just kinda rounds.. dunno

#18

0/0=1, which means you can divide by zero.

OMGWTFHAX

No it doesn't because you can't divide by zero therefore the answer is undefined, not 1. Try it on a calculator if you don't believe me. And it can't be a fraction because you can't have 0ths, because then your results are undefined.

#19

but x= .999999.... so it doesn't really matter what value you use. They are both interchangeable.

Ok ok you're right, I missed that first line of x = .99999

So in conclusion: .999 = 1 IF x=.999

Which isn't the same thing as just plain old 1 = .999

Sounds like TS just learned how to use variables kind of...

*Last edited by stinger12345 at Aug 6, 2008,*

#20

1+1=2

discuss.

discuss.

#21

The book Zero is about this type of stuff. Well at least it has a chapter one it.

#22

i'm not going to fry my brain cause school starts in 2 weeks..

#23

No it doesn't because you can't divide by zero therefore the answer is undefined, not 1. Try it on a calculator if you don't believe me. And it can't be a fraction because you can't have 0ths, because then your results are undefined.

wait, hes right, forget what I said.

#24

who gives a sh*t, the real gem we've found here is that 0/0=1

what the f*ck doodz!!1!?

EDIT: oh wait...i just read the posts above me

what the f*ck doodz!!1!?

EDIT: oh wait...i just read the posts above me

#25

No it doesn't because you can't divide by zero therefore the answer is undefined, not 1. Try it on a calculator if you don't believe me. And it can't be a fraction because you can't have 0ths, because then your results are undefined.

Bah, forgot about the fraction thing.

#26

When you subtract x, technically you have to use X, not an equivilant of x, at least in higher math....

so 10x - x = 9.9999-x

10 = 9.9999-x

I'm sure there is a rule that prevents this kind of thing, I just don't know it

Edit: Sounds like TS just learned how to use variables kind of...

THIS

so 10x - x = 9.9999-x

10 = 9.9999-x

I'm sure there is a rule that prevents this kind of thing, I just don't know it

Edit: Sounds like TS just learned how to use variables kind of...

THIS

*Last edited by Xaveir at Aug 6, 2008,*

#27

0/0=1, which means you can divide by zero.

OMGWTFHAX

No. because for it to be true 0x0 must equal 1, which it doesnt

#28

.99999 = 1x

That's what it should say...right? O.o

That's what it should say...right? O.o

#29

1+1=2

discuss.

OMGWTFHAX

Also on a more serious note:

.99999 = 1x

That's what it should say...right? O.o

1x=x

#30

I've been failing math for 5 years.

This makes me feel really dumb.

This makes me feel really dumb.

#31

No it doesn't because you can't divide by zero therefore the answer is undefined, not 1. Try it on a calculator if you don't believe me. And it can't be a fraction because you can't have 0ths, because then your results are undefined.

actually the term for this is indeterminate form (i think). cause the three possible answers are 0, infinity (undefined), or one. not to mention that the issue that it can equal any constant.

but yes... .9999 repeating is in fact one. the reason why is because in order to be defined as two separate numbers must have a number between them. What is in between them? an infinite number of 9's and then a 5? what the difference between 1 and .9999 repeating? an infinite, never ending series of 0's and then a 1? It makes more sense than you think.

you can try any form of math to solve this... I've used arithmetic, algebra and calculus and still came to the simple solution .9999 repeating=1. It is a fact... get over it!

#32

If you're using 0.999999... (repeating) then it's valid.

As the number of 9's go to infinity, the value goes to 1.

You can prove it using the formula for a sum of an infinite geometric series.

edit: http://en.wikipedia.org/wiki/0.999...

As the number of 9's go to infinity, the value goes to 1.

You can prove it using the formula for a sum of an infinite geometric series.

edit: http://en.wikipedia.org/wiki/0.999...

#33

I've been failing math for 5 years.

This makes me feel really dumb.

I'm with you on that one.

#34

If you put it into a calculator it doesn't work. Watch:

x = .99999999

10x = 9.9999999

10x - x = 9.9999999 - .99999999

9x = 8.99999991

x = 0.99999999

So...yeah, you're wrong.

x = .99999999

10x = 9.9999999

10x - x = 9.9999999 - .99999999

9x = 8.99999991

x = 0.99999999

So...yeah, you're wrong.

#35

why don't we post some of the Millennium Problems and give a goal to work with. Million bucks to anyone that can solve any of these! Dibbs on Riemann's Hypothesis!

#36

x = .99999999...

Multiply by 10

10x = 9.9999999...

subtract X

10x - x = 9.9999999... - .9999999...

Simplify

9x = 9

Simplify

x = 1

.99999... = 1

Discuss.

Why would you multiply by 10?

Besides in order for this to be right you should be able to plug your answer back into the equation.

10x1-1=9.9999... I don't think so. Someone correct me if I'm wrong.

#37

mathias07 knows what he's talking about, listen to him

#38

If you put it into a calculator it doesn't work. Watch:

x = .99999999

10x = 9.9999999

10x - x = 9.9999999 - .99999999

9x = 8.99999991

x = 0.99999999

So...yeah, you're wrong.

9.999 repeating minus .999 repeating does not equal 8.999 repeating.

9.999 repeating minus 1.00000009 would equal 8.999

Lrn2simplemath

#39

point?

and you technically can't subtract an infinite decimal sequence

#40

lol wtf maths is wrong lol i knew i never needed it very much anyway lol