Maybe I'm just tired, but I've worked through all my homework without much difficulty, but can't find out how to reach the answer here. I have the answer, but don't know how to get it.

It's college algebra and it's just factoring.

2x^3 + 6x^2 - 8x - 24

I factored out the 2
then tried grouping, which didn't work.
id help u but im just enetring freshamn year man srry
2(x^3+3x^2-4x-12)

I think that's all you can do... that's if I remember my math right, but from what I remember, there isn't any other way to continue factoring since there is no more like values...
i think you subtract the exponent 2 from 3 and then combine the like terms...
you tried synthetic division? might work here
is this equal to zero?
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2(x^3+3x^2-4x-12)

I think that's all you can do... that's if I remember my math right, but from what I remember, there isn't any other way to continue factoring since there is no more like values...

u can factor that down too, if i remember it right...

i wanna say its 2(x^2-4)(x+3)
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Last edited by deanwad at Aug 27, 2008,

2x2x2=8x
6x6=36x

8x+36x=44x
44x-8x=36x-24
idk that would be my best guess.
Quote by APE20
Maybe I'm just tired, but I've worked through all my homework without much difficulty, but can't find out how to reach the answer here. I have the answer, but don't know how to get it.

It's college algebra and it's just factoring.

2x^3 + 6x^2 - 8x - 24

I factored out the 2
then tried grouping, which didn't work.

2+3+6+2+8=22
22-24=-2.
if this is equal to zero, the best you're going to get is 2(x^3+3x^2-4x-12)=0.

It doesn't go any farther.
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Quote by the_man101

2x2x2=8x
6x6=36x

8x+36x=44x
44x-8x=36x-24
idk that would be my best guess.

well yea cuz once you subtract 2 from three you get one, and if any of you remember every variable has an "imaginary" 1 exponent

so after that you combine the like terms.....dont take my word though!!!
Quote by killer puppy
i think you subtract the exponent 2 from 3 and then combine the like terms...

Can't do that. You can divide by x, but that -12 is there after factoring out the two. I'm pretty sure all you can do is divide everything by 2.

EDIT: Nevermind. Forgot about synthetic division. Give that a try.
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u can factor that down too, if i remember it right...

i wanna say its 2(x^2-4)(x+3)

you need to factor x^2-4 soooo

2 (x + 2) (x - 2) (x + 3)

My mind is going. I can feel it.
Last edited by MTVget0FFtheAIR at Aug 27, 2008,
Common factor a 2x out of the first three terms to get the following;

2x(x^2 + 3x - 4) - 24

Now factor the quadratic in the brackets into two binomials to get the following;

2x(x+4)(x-1) - 24

That's as far as this will go
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Holy hell I am rusty at algebra hahaha
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I'm wrong. sik209 factored it into three binomials with a coefficient - which is correct
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you guys, check the problem i posted. if it works then it is right (i may have messed up in typing)

2(x+2)(x-2)(x+3)

EDIT: lol, took the pit 20 posts to get the answer to one algebra problem
Last edited by sik209 at Aug 27, 2008,
Quote by MTVget0FFtheAIR
2 (x + 2) (x - 2) (x + 3)

Oh yeah of course

There are kids at my engineering school that still don't know how to factor completely.
Sik and MTV were correct. I'm just tired and forgot how to factor a perfect square binomial. Like forgetting how to spell your brothers name, but in math.
Quote by SPrestigious
Common factor a 2x out of the first three terms to get the following;

2x(x^2 + 3x - 4) - 24

Now factor the quadratic in the brackets into two binomials to get the following;

2x(x+4)(x-1) - 24

That's as far as this will go

Nah you can't do that first step as it's all one function.