#1

Maybe I'm just tired, but I've worked through all my homework without much difficulty, but can't find out how to reach the answer here. I have the answer, but don't know how to get it.

It's college algebra and it's just factoring.

2x^3 + 6x^2 - 8x - 24

I factored out the 2

then tried grouping, which didn't work.

It's college algebra and it's just factoring.

2x^3 + 6x^2 - 8x - 24

I factored out the 2

then tried grouping, which didn't work.

#2

id help u but im just enetring freshamn year man srry

#3

2(x^3+3x^2-4x-12)

I think that's all you can do... that's if I remember my math right, but from what I remember, there isn't any other way to continue factoring since there is no more like values...

I think that's all you can do... that's if I remember my math right, but from what I remember, there isn't any other way to continue factoring since there is no more like values...

#4

i think you subtract the exponent 2 from 3 and then combine the like terms...

#5

you tried synthetic division? might work here

#6

is this equal to zero?

#7

2(x^3+3x^2-4x-12)

I think that's all you can do... that's if I remember my math right, but from what I remember, there isn't any other way to continue factoring since there is no more like values...

u can factor that down too, if i remember it right...

i wanna say its 2(x^2-4)(x+3)

*Last edited by deanwad at Aug 27, 2008,*

#8

add like terms?

2x2x2=8x

6x6=36x

8x+36x=44x

44x-8x=36x-24

idk that would be my best guess.

2x2x2=8x

6x6=36x

8x+36x=44x

44x-8x=36x-24

idk that would be my best guess.

#9

Maybe I'm just tired, but I've worked through all my homework without much difficulty, but can't find out how to reach the answer here. I have the answer, but don't know how to get it.

It's college algebra and it's just factoring.

2x^3 + 6x^2 - 8x - 24

I factored out the 2

then tried grouping, which didn't work.

2+3+6+2+8=22

22-24=-2.

#10

if this is equal to zero, the best you're going to get is 2(x^3+3x^2-4x-12)=0.

It doesn't go any farther.

It doesn't go any farther.

#11

add like terms?

2x2x2=8x

6x6=36x

8x+36x=44x

44x-8x=36x-24

idk that would be my best guess.

well yea cuz once you subtract 2 from three you get one, and if any of you remember every variable has an "imaginary" 1 exponent

so after that you combine the like terms.....dont take my word though!!!

#12

what is the answer anyways?

#13

i think you subtract the exponent 2 from 3 and then combine the like terms...

Can't do that. You can divide by x, but that -12 is there after factoring out the two. I'm pretty sure all you can do is divide everything by 2.

EDIT: Nevermind. Forgot about synthetic division. Give that a try.

#14

u can factor that down too, if i remember it right...

i wanna say its 2(x^2-4)(x+3)

you need to factor x^2-4 soooo

2(x+2)(x-2)(x+3) is final answer TS

#15

2 (x + 2) (x - 2) (x + 3)

/8thgrademath

/8thgrademath

*Last edited by MTVget0FFtheAIR at Aug 27, 2008,*

#16

Common factor a 2x out of the first three terms to get the following;

2x(x^2 + 3x - 4) - 24

Now factor the quadratic in the brackets into two binomials to get the following;

2x(x+4)(x-1) - 24

That's as far as this will go

2x(x^2 + 3x - 4) - 24

Now factor the quadratic in the brackets into two binomials to get the following;

2x(x+4)(x-1) - 24

That's as far as this will go

#17

Holy hell I am rusty at algebra hahaha

#18

I'm wrong. sik209 factored it into three binomials with a coefficient - which is correct

#19

you guys, check the problem i posted. if it works then it is right (i may have messed up in typing)

2(x+2)(x-2)(x+3)

EDIT: lol, took the pit 20 posts to get the answer to one algebra problem

2(x+2)(x-2)(x+3)

EDIT: lol, took the pit 20 posts to get the answer to one algebra problem

*Last edited by sik209 at Aug 27, 2008,*

#20

2 (x + 2) (x - 2) (x + 3)

/8thgrademath

Oh yeah of course

There are kids at my engineering school that still don't know how to factor completely.

#21

Sik and MTV were correct. I'm just tired and forgot how to factor a perfect square binomial. Like forgetting how to spell your brothers name, but in math.

#22

Common factor a 2x out of the first three terms to get the following;

2x(x^2 + 3x - 4) - 24

Now factor the quadratic in the brackets into two binomials to get the following;

2x(x+4)(x-1) - 24

That's as far as this will go

Nah you can't do that first step as it's all one function.