#1

Can anyone help?

The problem is:

(1 over the cosecant of theta) all over (cos of theta squared plus sin of theta squared)

Can anyone give me any tips on simplifying this?

Thanks.

The problem is:

(1 over the cosecant of theta) all over (cos of theta squared plus sin of theta squared)

Can anyone give me any tips on simplifying this?

Thanks.

#2

cos squared + sin squared = 1

A lot easier if you do that

A lot easier if you do that

#3

(leaves confused as hell)

#4

I thought that was right, but then that would give us:

(1 over the cosecant of theta)

Right? And I don't believe that can be simplified.

(1 over the cosecant of theta)

Right? And I don't believe that can be simplified.

#5

:/

Cosign....

Cosign....

#6

Do you have a table of trig. identities?

#7

I know the answer.

However, it will cost you a small planet.

And maybe your housepet.

However, it will cost you a small planet.

And maybe your housepet.

#8

"If you don't know the answer say Purple"

-Jesus

-Jesus

#9

1/cosec = sin

#10

I thought that was right, but then that would give us:

(1 over the cosecant of theta)

Right? And I don't believe that can be simplified.

Yeah that's right. And we know (hopefully ) that cosec is 1/sin, so we have 1/(1/sin)

which equals sin theta.

EDIT: I dunno why I feel the urge to do maths in the holidays

#11

Thanks very much

#12

well, because (im gonna use O as theta) 1/csc(O) in fact equals (because csc(O)=1/sin(O)) sin(O). And, as we know with the pythagorean thm, (sin(O)^2)+(cos(O)^2)=1. So, simply by reducing, we have sin(O)/1, which in fact equals sin(O).

#13

Yeah that's right. And we know (hopefully ) that cosec is 1/sin, so we have 1/(1/sin)

which equals sin theta.

you bastard i was just about to post the right answer curse you!!