Can anyone help?
The problem is:

(1 over the cosecant of theta) all over (cos of theta squared plus sin of theta squared)

Can anyone give me any tips on simplifying this?
Thanks.
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cos squared + sin squared = 1

A lot easier if you do that
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I thought that was right, but then that would give us:

(1 over the cosecant of theta)

Right? And I don't believe that can be simplified.
What do we tell our children? Look before you leap. Stop and think. Don't judge a book by its cover. We believe that we are always better off gathering as much information as possible and spending as much time as possible in deliberation.
Do you have a table of trig. identities?
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1/cosec = sin
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I thought that was right, but then that would give us:

(1 over the cosecant of theta)

Right? And I don't believe that can be simplified.

Yeah that's right. And we know (hopefully ) that cosec is 1/sin, so we have 1/(1/sin)
which equals sin theta.

EDIT: I dunno why I feel the urge to do maths in the holidays
Up The Boro!
Thanks very much
What do we tell our children? Look before you leap. Stop and think. Don't judge a book by its cover. We believe that we are always better off gathering as much information as possible and spending as much time as possible in deliberation.
well, because (im gonna use O as theta) 1/csc(O) in fact equals (because csc(O)=1/sin(O)) sin(O). And, as we know with the pythagorean thm, (sin(O)^2)+(cos(O)^2)=1. So, simply by reducing, we have sin(O)/1, which in fact equals sin(O).
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Yeah that's right. And we know (hopefully ) that cosec is 1/sin, so we have 1/(1/sin)
which equals sin theta.

you bastard i was just about to post the right answer curse you!!
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