#1
Can anyone help?
The problem is:

(1 over the cosecant of theta) all over (cos of theta squared plus sin of theta squared)

Can anyone give me any tips on simplifying this?
Thanks.
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#3
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#4
I thought that was right, but then that would give us:

(1 over the cosecant of theta)

Right? And I don't believe that can be simplified.
What do we tell our children? Look before you leap. Stop and think. Don't judge a book by its cover. We believe that we are always better off gathering as much information as possible and spending as much time as possible in deliberation.
#8
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#9
1/cosec = sin
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#10
Quote by Pharoah
I thought that was right, but then that would give us:

(1 over the cosecant of theta)

Right? And I don't believe that can be simplified.


Yeah that's right. And we know (hopefully ) that cosec is 1/sin, so we have 1/(1/sin)
which equals sin theta.

EDIT: I dunno why I feel the urge to do maths in the holidays
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#11
Thanks very much
What do we tell our children? Look before you leap. Stop and think. Don't judge a book by its cover. We believe that we are always better off gathering as much information as possible and spending as much time as possible in deliberation.
#12
well, because (im gonna use O as theta) 1/csc(O) in fact equals (because csc(O)=1/sin(O)) sin(O). And, as we know with the pythagorean thm, (sin(O)^2)+(cos(O)^2)=1. So, simply by reducing, we have sin(O)/1, which in fact equals sin(O).
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#13
Quote by Oddsbodkins
Yeah that's right. And we know (hopefully ) that cosec is 1/sin, so we have 1/(1/sin)
which equals sin theta.

you bastard i was just about to post the right answer curse you!!
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