#1

pam jogged up a hill at 6 km /h and then jogged back down at 10 km / h. how many kilometers did she travel in all if her total jogging time was 1 h 20 min.

Please explain how you got the answer . THanks

Please explain how you got the answer . THanks

#2

Who gives a s

*h*__it how far Pam jogged?__
#3

Well you would need to know at what time she stopped jogging up the hill and turned around.

#4

Is that all you know? Is the upwards as long as downwards?

#5

Well it depends on how big the hill was and how long she was jogging up and down. If she jogged up it for an 1 hour its going to be a different answer than if she only jogged up it for 40 mins.

#6

Is that all you know? Is the upwards as long as downwards?

yes and that the distance is equal (going up and down)

#7

no you wouldn't, because you know how long the entire trip was, and she turned around. you can calculate how far she walked, and from there it's easy.

#8

*insert woman joke here*

But seriously, I think there's too little info to find out the answer.

But seriously, I think there's too little info to find out the answer.

#9

Is that all you know? Is the upwards as long as downwards?

How could it not be? Pam jogged up the hill and upon reaching the top, the hill grew a further 1km. Pam was very thankful that this didn't happen on the way up.

#10

You can't find it out since the time she jogged up/down was not given..

#11

She jogged 10 km, 50 minutes up and 30 minutes down the hill...

#12

*insert woman joke here*

But seriously, I think there's too little info to find out the answer.

by saying she goes up the hill and down it again... the information clearly suggests that the distance is the same, since it is the same hill

#13

She jogged 10 km, 50 minutes up and 30 minutes down the hill...

thanks dude

#14

PAM BEASLEY

as for the question, its missing a very important part of information that would be needed to answer the question. i think.

edit: or not.

as for the question, its missing a very important part of information that would be needed to answer the question. i think.

edit: or not.

#15

ok, so

if she walked half way at 6 km/h, and walked the other half at 10 km/h, her average speed would be 8 km/h

and she walked for an hour and 20 minutes (1 and 1/3 hours)

so her total distance traveled would be: 8 times 1 and 1/3

which is...10.66667 km

im pretty sure

if she walked half way at 6 km/h, and walked the other half at 10 km/h, her average speed would be 8 km/h

and she walked for an hour and 20 minutes (1 and 1/3 hours)

so her total distance traveled would be: 8 times 1 and 1/3

which is...10.66667 km

im pretty sure

#16

You can't find it out since the time she jogged up/down was not given..

i think because up a hill and down again that you can assume the two distances are the same. they don't think of everything within a question. with that being the case, half was at 6, the other half at 10, so an average of 8. if you run at an average of 8km/h for 1 hour 20 minutes, you cover 10 and 2/3 of a kilometer.

but yes, the exact distances were not given, so you can't work it exactly.

edit: ^^ damn a blast it!

#17

I'm too lazy to solve it completely but...

You have v1 = 6 and v2 = 10

then you have t1= the time it took to get up and t2 = the time it took to get down again

and x = the number of kilometers ran.

So v1*t1 + v2*t2 = x

now if you can find 2 different relations between t1 and t2, you'll get 2 equasions with 2 unknown factors (which will be t1 and x or t2 and x), and from that you can get x

The 2 relations are:

a)t1+t2=4/3 (because you ran 4/3rd of an hour in total. I'm not using SI units, but you don't have to :p)

b)t1=(13/3)*t2 (If she'd run 1 hour, then getting up would take 4 more kilometers than getting off. But she ran 4/3rd of an hour, so you have to add 1/3rd of a kilometer to that time. So it's 4 and 1/3rd hours more to get up than to get off the hill. Or in easyer numbers 13/2 hours more).

So you can put that in there and you'll get 2 equasions which you can then solve

You have v1 = 6 and v2 = 10

then you have t1= the time it took to get up and t2 = the time it took to get down again

and x = the number of kilometers ran.

So v1*t1 + v2*t2 = x

now if you can find 2 different relations between t1 and t2, you'll get 2 equasions with 2 unknown factors (which will be t1 and x or t2 and x), and from that you can get x

The 2 relations are:

a)t1+t2=4/3 (because you ran 4/3rd of an hour in total. I'm not using SI units, but you don't have to :p)

b)t1=(13/3)*t2 (If she'd run 1 hour, then getting up would take 4 more kilometers than getting off. But she ran 4/3rd of an hour, so you have to add 1/3rd of a kilometer to that time. So it's 4 and 1/3rd hours more to get up than to get off the hill. Or in easyer numbers 13/2 hours more).

So you can put that in there and you'll get 2 equasions which you can then solve

*Last edited by Base Ics at Sep 7, 2008,*

#18

wow, this looks easy, it would be usualy.. but all i can think of now is fap, ug, fail, russel wtf.. i think i spent too much time in here

#19

Use vectors.

#20

who cares how far Pam jogged if she's not in the kitchen!!!!

seriously, I don't know the answer, but here's a cookie for support!!!!

seriously, I don't know the answer, but here's a cookie for support!!!!

#21

Math thread?

#22

The hill is 5km tall, so she traveled 10km in total

Solution if you're interested

6x + 10y = 80

80 is the number of minutes, 6x represents the uphill climb, and 10y represents the downhill

Now let x = y, so that both parts are equal

The equation becomes 16x = 80 => x = 5

Now to check

If she climbed 5km uphill then she would spend 50 minutes

Now if she traveled downhill then it would take her 30 minutes

Which adds to 80 minutes

Solution if you're interested

6x + 10y = 80

80 is the number of minutes, 6x represents the uphill climb, and 10y represents the downhill

Now let x = y, so that both parts are equal

The equation becomes 16x = 80 => x = 5

Now to check

If she climbed 5km uphill then she would spend 50 minutes

Now if she traveled downhill then it would take her 30 minutes

Which adds to 80 minutes

#23

pam jogged up a hill at 6 km /h and then jogged back down at 10 km / h. how many kilometers did she travel in all if her total jogging time was 1 h 20 min.

Please explain how you got the answer . THanks

10x = 6(4/3-x)

10x = 8 - 6x

16x = 8

x = 1/2

x is time going down. She took 50 minutes up and 30 minutes down for a total of 80 minutes (1 hr 20min). 50 minutes at 6 km/h is 5 km (50/60 * 6) and 30 minutes at 10 km/h is... also 5 (the hills the same length and just to check 30/60 * 10) Enjoy!

EDIT: Seems I was beaten while trying to type out math lol.

#24

Sniped, you made a mistake

6x + 10y doesn't equal to 80

you multiplied the speeds (km/h) with distance (km) to get time (h)

that isn't right

what you have to do here is multiply the speeds (km/h) with the time (h) to get distance (km)

My method is correct, it's on the previous page

6x + 10y doesn't equal to 80

you multiplied the speeds (km/h) with distance (km) to get time (h)

that isn't right

what you have to do here is multiply the speeds (km/h) with the time (h) to get distance (km)

My method is correct, it's on the previous page

#25

Well no one can do that, because theyre all busy staring at her boobs jiggle up and down.

But seriously, I dont know. If I wrote it out I could figure it out, but I'm too lazy too. And cuz ^ that guy got it. The way I would've done it.

But seriously, I dont know. If I wrote it out I could figure it out, but I'm too lazy too. And cuz ^ that guy got it. The way I would've done it.

#26

10x = 6(4/3-x)

10x = 8 - 6x

16x = 8

x = 1/2

x is time going down. She took 50 minutes up and 30 minutes down for a total of 80 minutes (1 hr 20min). 50 minutes at 6 km/h is 5 km (50/60 * 6) and 30 minutes at 10 km/h is... also 5 (the hills the same length and just to check 30/60 * 10) Enjoy!

EDIT: Seems I was beaten while trying to type out math lol.

And this guy's method is correct too

difference: his is quicker and easyer

GZ m8 xD

#27

she runs the same distance up as she does down.

so running at speed 6kmh she runs x km

running at 10kmh she runs x km aswell

say after 50 mins at 6kmh that is 5km,

leaving 30 mins left over at 10kmh, which is another 5km, therefore total distance is 10km

EDit: shit other people done it before me, i never read the secdond page lol

so running at speed 6kmh she runs x km

running at 10kmh she runs x km aswell

say after 50 mins at 6kmh that is 5km,

leaving 30 mins left over at 10kmh, which is another 5km, therefore total distance is 10km

EDit: shit other people done it before me, i never read the secdond page lol