I have a homework problem I'm stuck on for my math class.

I need to find:

the limit as x approaches 5 from the + of f(x).

f(x) = e^x /((x-5)^3)

Any help?
Quote by Sonicxlover
I once told a Metallica fan I liked Megadeth, and he stabbed me 42 times.
I could have helped you last year.

Unfortunately, everything I learnt at school has leaked out my ears, and I'll be surprised if I get anywhere in life. And guess what? It'll happen to you! Then you'll be praying for death.

Good luck!

DON'T MAKE ME DESTROY YOU!

___________________________________________________

TURN OFF YOUR MIND RELAX AND FLOAT DOWNSTREAM

Quote by Scumbag1792
My God, this must be the smartest/greatest guy ever.
ohai little sig.
well, the answer is infinity because you'd end up with e^x/a really small number iuf you chose like 5.0001 as x.
multiply out the denominator, and change the top to a natural log (ln). then plug in 5 for x
Thanks for those of you that helped me. I got it now
Quote by Sonicxlover
I once told a Metallica fan I liked Megadeth, and he stabbed me 42 times.
Lo hopital's rule? that might help out, mind you, you might have to take the 3 derivative or so
Quote by bigwilly
Thanks for those of you that helped me. I got it now

It was 42 wasn't it?
Quote by maggot9779

42

hitch hikers guide to the galaxy... classic

yeah, i hate limits, stupid calc
Warning: The above post may contain lethal levels of radiation, sharp objects and sexiness.
Proceed with extreme caution!
Quote by TrUe MeTaL FaN
wut in the hell does that mean ahh im in 10th grade geometry

if your school's curriculum is like mine, you'll be doing that next year in algebra 2
Quote by Samdunhamss
Lo hopital's rule? that might help out, mind you, you might have to take the 3 derivative or so

Do you even know what L'Hopital's rule is used for?
Quote by denizenz
I'll logic you right in the thyroid.

Art & Lutherie
you need 0/0 or infinity/infinity for l'hopital bud, and that doesn't really happen here
I think it's 3.

Yeah, I'm going with 3.
use l'hopital's rule

when you've got a limit of a fraction where you've got 0 in the denominator you can differentiate both the numerator and denominator and the value will stay the same

so we've got a/b
a= e^x
b = (x-5)^3

and we just keep differentiating them until we get a b != 0 when we put in x=5

a' = e^x
b' = 3*(x-5)^2

a'' = e^x
b'' = 6*(x-5)^1

a''' = e^x
b''' = 6

so limit x->5 for (e^x /((x-5)^3)) = limit x->5 for (e^x/6) = 24.7355265

wikipedia the rule
Quote by seljer
use l'hopital's rule

when you've got a limit of a fraction where you've got 0 in the denominator you can differentiate both the numerator and denominator and the value will stay the same

so we've got a/b
a= e^x
b = (x-5)^3

and we just keep differentiating them until we get a b != 0 when we put in x=5

a' = e^x
b' = 3*(x-5)^2

a'' = e^x
b'' = 6*(x-5)^1

a''' = e^x
b''' = 6

so limit x->5 for (e^x /((x-5)^3)) = limit x->5 for (e^x/6) = 24.7355265

wikipedia the rule

Can't use it. If the question is lim(x->a) of f(a)/g(a) then one condition is:
f(a) = g(a) = 0 or [ lim f(x) = plusminus infinity and lim g(x) = plusminus infinty ]

(x-5) becomes arbitrarily small as x tends to 5 from above. That means that (x-5)^3 becomes even smaller.

We can treat the top e^5 as constant.

Means that it is a constant divided by an arbitrarily small constant that is slightly above 0 (i.e. epsilon). That equals infinity.
Quote by bassplayer33333
Sinisa Rules all.

Quote by zbest
That is part of the reason that the mafia does so much drug trafficing, its so they wont die of hunger because they dont have anything.
Quote by sinisa
Can't use it. If the question is lim(x->a) of f(a)/g(a) then one condition is:
f(a) = g(a) = 0 or [ lim f(x) = plusminus infinity and lim g(x) = plusminus infinty ]

(x-5) becomes arbitrarily small as x tends to 5 from above. That means that (x-5)^3 becomes even smaller.

We can treat the top e^5 as constant.

Means that it is a constant divided by an arbitrarily small constant that is slightly above 0 (i.e. epsilon). That equals infinity.

bah, its been a year since i took that class
Quote by seljer
bah, its been a year since i took that class

tisk tisk

As my old 1st stage maths prof would say (with a thick chinese accent and a beard like pei mey, no shit):