#1
Can u work this out, we were meant to work it out for our maths homework:

From a book, a number of consecutive pages are missing.
The sum of the page numbers of these pages is 9808.
Which pages are missing?

Thanks to who gets it first xD
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#3
only page 9808 is missing.

or

the pages 291 up to and including 322 are missing.

this is the internet you tart.
#4
There are 32 pages missing starting with page 291

Let X = a page number
Therefore X + 1 = the next consecutive page, x+2, the page after that X+n = the last page and n+1 = total number of pages

If two pages were missing the equation would be

x + (x+1) = 9808
2x + 1 = 9808
2x = 9807
x = 4903.5 which obviously is wrong since you can't be missing half a page( well you can, but you know what I mean)

3 pages would be
x + (x+1) + (x+2) = 9808
3x+3= 9808
4 would be
x + (x+1) + (x+2) + (x+3) = 9808
4x+6

see the pattern of the second nomial? It's a simple arithmetic sequence:
F(n) = Sum (0...N)
and how it relates to the coefficient of the first?

So a general formula can be create thus:
nX + F(n-1) = 9808
nX = 9808 - F(n-1)
X = (9808-F(n-1)) / n

n = number of pages
X = begining page
#5
By "these pages" you're referring to the missing pages. Either that or the grammar is wrong or I'm wrong :/
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#9
Quote by Thy Woodzy
There are 32 pages missing starting with page 291

Let X = a page number
Therefore X + 1 = the next consecutive page, x+2, the page after that X+n = the last page and n+1 = total number of pages

If two pages were missing the equation would be

x + (x+1) = 9808
2x + 1 = 9808
2x = 9807
x = 4903.5 which obviously is wrong since you can't be missing half a page( well you can, but you know what I mean)

3 pages would be
x + (x+1) + (x+2) = 9808
3x+3= 9808
4 would be
x + (x+1) + (x+2) + (x+3) = 9808
4x+6

see the pattern of the second nomial? It's a simple arithmetic sequence:
F(n) = Sum (0...N)
and how it relates to the coefficient of the first?

So a general formula can be create thus:
nX + F(n-1) = 9808
nX = 9808 - F(n-1)
X = (9808-F(n-1)) / n

n = number of pages
X = begining page



I agree although you way overexplained :-X

It would have been just as simple to say

nx + (n-1) = 9809
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#10
Quote by dannyniceboy
I agree although you way overexplained :-X

It would have been just as simple to say

nx + (n-1) = 9809


He pasted that from another website. Not his explanation.
#11
well I don't see why I should bother solving it since only the first one to get it gets your thanks, but probably the easiest way is just (x)+(x+1)+(x+2)=9808 and simplify that to get the first page and just add 1 then 1 again to get the others.
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#12
Quote by blair30
He pasted that from another website. Not his explanation.


This. I take no credit.