#1
im doing a level physics and got set this for homework

an object is acted upon by forces 9.6n and 4.8n, with an angle of 40(degrees) between them. Draw a vector diagram of these forces using a scale of 1cm to 1n. complete the vector diagram to determine the magnitude of the resultant force acting on the object, measure the angle between the resultant force and the 9.6n force

basically, im stuck on what force goes on what axis of the diagram, is it a 90(degree) triangle? i just need someone to explain what to draw


thanks (sorry for wall of text)
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#2
draw a 9.6cm line wherever you feel like it

then 40degrees of from on it draw a 4.8cm line


to find the resultant force draw a parallelogram from those 2 lines you just drew
the resultant force is the diagonal
measure length the diagonal, measure the angle between it and the first line


edit: and draw the little vector arrow things on all vectors
Last edited by seljer at Sep 26, 2008,
#3
Quote by seljer
draw a 9.6cm line wherever you feel like it

then 40degrees of from on it draw a 4.8cm line


Do that then use trigonometry to find the resultant.
#4
if they dont give any indication as to what direction either force is going, than either A) it doenst matter as long as you have the angle between them right, or B) just assume the first force to be at 0 degrees (with force that would be due east on a reg compass). not quite sure how to do it right without knowing your teachers methods and preferences.
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#6
Quote by ms2492
Do that then use trigonometry to find the resultant.


eh, his instructions say he should measure them

but yeah, trignometry ftw
your answer should be about 13.82cm and an angle of about 11°55'
#7
the instructions are really shat

im just going to do what seljer said and hope its all good
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