#1

____

abcd is a 4 digit number b=9 c=7 and the number can be divided by 45, what is the number (translating from another language here so sorry if it doesn't make perfect sense).

hope you guys can help out.

abcd is a 4 digit number b=9 c=7 and the number can be divided by 45, what is the number (translating from another language here so sorry if it doesn't make perfect sense).

hope you guys can help out.

#2

math thread

#3

2970

#4

could you please include how you solved that?

#5

any number as long as its has a97d any number can be divided by 45 unless they mean divided by 45 and comes out to a whole number its 2970

#6

Come out as a whole number is exactly what they mean but how do you solve the whole thing, I'd like to get more then just the answer please.

#7

You work out all the multiples of 45 up to the highest with 4 digits, then look for ones with in the x97x format.

#8

i got excel to work this out for me

45

90

135

180

225

270

315

360

405

450

495

540

585

630

675

720

765

810

855

900

945

990

1035

1080

1125

1170

1215

1260

1305

1350

1395

1440

1485

1530

1575

1620

1665

1710

1755

1800

1845

1890

1935

1980

2025

2070

2115

2160

2205

2250

2295

2340

2385

2430

2475

2520

2565

2610

2655

2700

2745

2790

2835

2880

2925

2970

45

90

135

180

225

270

315

360

405

450

495

540

585

630

675

720

765

810

855

900

945

990

1035

1080

1125

1170

1215

1260

1305

1350

1395

1440

1485

1530

1575

1620

1665

1710

1755

1800

1845

1890

1935

1980

2025

2070

2115

2160

2205

2250

2295

2340

2385

2430

2475

2520

2565

2610

2655

2700

2745

2790

2835

2880

2925

2970

#9

____

abcd is a 4 digit number b=9 c=7 and the number can be divided by 45, what is the number (translating from another language here so sorry if it doesn't make perfect sense).

hope you guys can help out.

a<10

d<10

1000a+100b+10c+d=*45

1000a+900+70+d=*45

1000a+*45+70+d=*45

1000a+d+70=*45-

(*45+10)a+d+70=*45

*45a+10a+d+(*45+25)=*45

10a+d+25=*45

10a+d+(*45-20)=*45

10a+d-20=*45

10a+d=*45+20

I guess you can try from that point...10a+d<100 so *45+20<100

so *45+20 is either 65 or 20

so the number is either 6975 (10*6+5=65) or 2970 (10*2+0=20)

I don't know if you can do it without trying numbers yourself...

#10

Over 9000

amidoinitrite?

amidoinitrite?

#11

Use the table of 45 like mrjimborinsane did.

#12

Here's the solution.

a97d = 45*x

a*1000 + 970 + d = 45*x

970/45 = 21*45 + 25

a*1000 / 45 = a(45*22 + 10)

a*10 + 25 + d = 45 * (-22a-21+x)

Now all we need to find is what a and d are.

a*10 + 25 + d = 45 * y (multiple of 45)

Need to find suitable numbers so that both a and d are single positive digits

If y = 1

a = 2 and d = 0

if y=2

a = 6 and d = 5

If y=3, then there is no relationship that satisfies both a and d as single digits.

The answers are:

2970

6975

a97d = 45*x

a*1000 + 970 + d = 45*x

970/45 = 21*45 + 25

a*1000 / 45 = a(45*22 + 10)

a*10 + 25 + d = 45 * (-22a-21+x)

Now all we need to find is what a and d are.

a*10 + 25 + d = 45 * y (multiple of 45)

Need to find suitable numbers so that both a and d are single positive digits

If y = 1

a = 2 and d = 0

if y=2

a = 6 and d = 5

If y=3, then there is no relationship that satisfies both a and d as single digits.

The answers are:

2970

6975