#1

Yes, I've Googled, nothing helpful has came up. All I need is the formula - that I've forgot. Maybe it's sine, cosine or tangent...

I've drawn it up in paint.

Please don't

Cheers for any help!

I've drawn it up in paint.

Please don't

*only*tell me the answer, I want to know how to do these by myself. All it is is a simple formula... eg. (height x width) divided by 304.1982...Cheers for any help!

#2

tanx=opposite/adjacent

Sohcahtoa, foo'.

Sohcahtoa, foo'.

#3

I think it's Tan Theta 4 over 2.5

#4

Ah, sohcahtoa, now I remember. God how they pushed that into us in grade 9...

So tangent x (4 divided by 2.5)?

So tangent x (4 divided by 2.5)?

#5

tan ? = 4km/2.5km

that is, tan inverse 4/2.5 i think

edit: i mean the unknown angle is tan inverse 4/2.5

that is, tan inverse 4/2.5 i think

edit: i mean the unknown angle is tan inverse 4/2.5

#6

tan ? = 4/2.5

therefore... ? = tan inverse 4/2.5

WHERE IS MY COOKIE?!

therefore... ? = tan inverse 4/2.5

WHERE IS MY COOKIE?!

#7

tan^(-1)(opposite/adjacent)=[theta]

EDIT: Erm, that's a little unclear looking. That's an inverse tangent.

.....-1

tan (opp/adj)

EDIT: Erm, that's a little unclear looking. That's an inverse tangent.

.....-1

tan (opp/adj)

#8

I don't get it - tan inverse?

#9

**** it. My post sucks. Get a graphing calculator, hit 2nd -> tan(x) and input (opp/adj) into the argument.

#10

^ It shows up as Tan-1 on the calculator.

At least I think it does...

At least I think it does...

#11

I don't get it - tan inverse?

it should be on your calculator somewhere. it's a tan with a tiny "-1" on it

#12

tan^(-1)(opposite/adjacent)=[theta]

EDIT: Erm, that's a little unclear looking. That's an inverse tangent.

.....-1

tan (opp/adj)

Ah, okay - in Australia my maths teacher just calls it "tan-1," haha...

Anyone got a good online scientific calculator? I don't have one at home, and 'Calculator.com' sucks.

So it's (tan-1)(4/2.5) to find the angle I'm looking for?

#13

I don't get it - tan inverse?

Should look like tan

^{-1}on your calculator.

Basically, you put a degree value into tan, and it spits out the corresponding number. You put that number into inverse tan, and it should spit out that original degree value. So inverse tan is basically the opposite function to tan.

And that's really a shitty explanation, but it's 2:30AM, so cut me some slack.

Edit: UG doesn't support superscript/subscript tags? Meh.

#14

I'm pretty sure I've got it now, thanks for all of your help.

I feel a little less dumb, and a bit more knowledgeable now. Trust me, I'm a really good English, music and art student, but terrible at maths and science.

I feel a little less dumb, and a bit more knowledgeable now. Trust me, I'm a really good English, music and art student, but terrible at maths and science.

#15

So it's (tan-1)(4/2.5) to find the angle I'm looking for?

yup

#16

Not Phyics, mathematics, repeat this is mathematics, not physics

Trigonometrey to be exact

Trigonometrey to be exact

#17

Not Phyics, mathematics, repeat this is mathematics, not physics

Trigonometrey to be exact

Basic physics is literally just the application of mathematics to describe the motion/behaviour of physical objects. Mathematics is not necessarily physics, but physics is necessarily mathematics.

#18

59 degrees

EDIT:

It it Physics, Physics is pretty much Mathematics though - this is just applying trig at the moment.

EDIT:

It it Physics, Physics is pretty much Mathematics though - this is just applying trig at the moment.

*Last edited by BGSM at Oct 6, 2008,*

#19

Basic physics is literally just the application of mathematics to describe the motion/behaviour of physical objects. Mathematics is not necessarily physics, but physics is necessarily mathematics.

That's not physics though, that has nothing to do with the movement of an object it's purely about angles, therefore not physics.

#20

That's not physics though, that has nothing to do with the movement of an object it's purely about angles, therefore not physics.

True. I wasn't thinking specifically about his post. Perhaps it's part of a larger problem?

#21

tanx=opposite/adjacentSohcahtoa, foo'.

Sex On Hard Courts Always Hurts, Try Other Areas.

You'll never forget it again

*Last edited by el-ECTRO at Oct 6, 2008,*

#22

Sex On Hard Courts Always Hurts, Try Other Places.

You'll never forget it again

Man, I always learned "some old horse caught a horse taking oats away."

Your way wins by about thirteen thousand arbitrary units.

#23

Yeah, it's for a larger problem. I needed to find out the angle to state the displacement from A to C - East58degrees.

#24

um E=mc²? wait uh [insert crazy mathematical gibberish here].

#25

Someone has probably already said this, but this is not physics. It's trigonometry...lern 2 math

#26

It could be a vector problem. Which is physics.

#27

It could be a vector problem. Which is physics.

TS, is it a vector problem?

#28

Yes, it is.

#29

Oh...Well I stand corrected, goes to show what I get for not reading past the first post :-)

#30

Haha, no problem. I'm onto question 7 now - which is really annoying. You have to work from a tiny graph, and there's no formula that you can work from - so the answer is most likely inaccurate.

#31

Sex On Hard Courts Always Hurts, Try Other Areas.

You'll never forget it again

Somehow i don't think I will, but now when ever i'm in an exam i'm going to get distracted, dam you!!!

btw TC, inverse tan^-1 is the same as 1 over tan... I don't know if that clears anything for you, but oh well.

#32

It could be a vector problem. Which is physics.

It only shows distances though....

Yes, it is arctangent of 4/2.5 ....

#33

vectors is still maths.

Ever take calc in three dimensions?

Ever take calc in three dimensions?