so i got two problems im a little stuck on for some reason. im to find the derivatives of each of the following:

1. y=[(x^2)-3x]cos(2x+10)
i only got to [(x^2)-3x][-sin(2x+1)] + [2x-3][cos(2x+1)] before completely forgetting what i had to do next

2. y= [sqrt(x)] / (x - pi)
and here i just couldnt think of wtf to do.

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I'm really tired and don't feel like working them out right now, but you need to use the quotient rule on the second one.

yeah i know that, but if i take the derivative of (x - pi) i would just get (1 - 1) no? and that just doesnt seem right to me
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yeah i know that, but if i take the derivative of (x - pi) i would just get (1 - 1) no? and that just doesnt seem right to me

No, the derivative of pi is zero because it's a constant.
isnt the derivative of (x - pi) just 1.... the pi becomes 0

EDIT for spelling
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yeah alright that makes some sense now, i just kept thinking of pi as a variable that would go to 1 just like x would.
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You can't have sex with her personality.
Goddammit does no one read the stickies?!?

Maths and help thread, my main man.

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so i got two problems im a little stuck on for some reason. im to find the derivatives of each of the following:

1. y=[(x^2)-3x]cos(2x+10)
i only got to [(x^2)-3x][-sin(2x+1)] + [2x-3][cos(2x+1)] before completely forgetting what i had to do next

2. y= [sqrt(x)] / (x - pi)
and here i just couldnt think of wtf to do.