So yeah, I'm in Algebra 2 again, I don't know how to solve a quadratic function in vertex form.

The problem I have is y=3(x+4)squared+5

I know the vertex is 4, 5

ehh?
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What do you mean solve? Find the value of x or graph?
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Quote by Ostinattos

=O no, but this is MY homework thread

I guess I have to graph it, btw.
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x=37
y=19
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wiliscool is just plain dumb
Isn't homework supposed to, you know, be done by yourself? Isn't it, I don't know, breaking the rules having someone do it for you?
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vertex form is y= a[(x-h)^2]+k the point (h,k) is the vertex so as you wrote your equation, the vertex is (-4,5)

and ya, what do you mean by solve, find roots?
I wish someone would teach me
And we will weave in and out of sanity unnoticed
Swirling in blissfully restless visions of all our bleary progress
ill help you, what exactly do you want to know? If you just have to graph it, start at (-4,5) and then plot some points, pick an x, then run it through the equation to get the y that goes with that x. you will have to be careful to pick x's that work though. for instance, (assuming y=f(x))

f(0)=53 might be tough to graph but
f(-4)=5
f(-5)=8 so on, so on
Solve usually means find the zeroes. If you distribute and what not you get. y=3(x^2)+24x+53
That might be wrong but if its right you then can use quadratic formula on it and get yerself some zeroes

EDIT: math sucks just graph it and look for where it crosses the x axis
It's kind of hard to explain over the internet but you would move it left 4, up 5 and shrink it horiz. by a factor of 3.

Edit:
Quote by -=Croatoan=-
Solve usually means find the zeroes. If you distribute and what not you get. y=3(x^2)+24x+53
That might be wrong but if its right you then can use quadratic formula on it and get yerself some zeroes

EDIT: math sucks just graph it and look for where it crosses the x axis

It isn't going to have any zeros.
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Last edited by Spydr at Oct 20, 2008,
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Quote by Spydr
It's kind of hard to explain over the internet but you would move it left 4, up 5 and shrink it horiz. by a factor of 3.

Edit:

It isn't going to have any zeros.

Damn, didnt think that one through. I dont like imaginary numbers. You can still use quadratic formula but the numbers are all screwy... I think.

EDIT: Quad form gets you 24 plus or minus 2i(Square root of 15)/6
It looks really confusing if you don't write it out.
Last edited by -=Croatoan=- at Oct 20, 2008,
ya you can tell there will be no real roots b/c the vertex is at 5 and it opens up