#1

2NH4NO3 --------> 2N2 + O2 + 4H20

So, you're given 12.6 g of NH4NO3 and asked to find the g for each of the products.

Now, I know how to do this (at least I thought so) but I'm not getting the right answers except for the weight of N2 (4.41 g). Yes I am looking at the mol ratio so that when I go from the # of mol of NHaNO3 to O2 I divide it by 2..but I'm just not getting the right answers..the hell?

So, you're given 12.6 g of NH4NO3 and asked to find the g for each of the products.

Now, I know how to do this (at least I thought so) but I'm not getting the right answers except for the weight of N2 (4.41 g). Yes I am looking at the mol ratio so that when I go from the # of mol of NHaNO3 to O2 I divide it by 2..but I'm just not getting the right answers..the hell?

#2

2NH4NO3 --------> 2N2 + O2 + 4H20

So, you're given 12.6 g of NH4NO3 and asked to find the g for each of the products.

N - 14 x 4 = 56gms

H - 4 x 2 = 8 gms

0 - 16 x 6 = 96 gms

160 gms

Gives

N - 14 x 2 = 28 gms

0 - 16 x 2 = 32 gms

H - 4 x 1 + 16 x 4= 64 gms

160 gms NH4NO3 = 32 GMS O2

12.6 GMS = X GMS

[ Unitary method ]

160/12.6 = 32/x

= 2.52 gms

160 gms NH4NO3 = 64 gms h20

12.6gms = x gms

160/12.6 = 64/x

= 5.04 gms

Is that correct???????????/

im a 14 year old indian by the way

lol

So, you're given 12.6 g of NH4NO3 and asked to find the g for each of the products.

N - 14 x 4 = 56gms

H - 4 x 2 = 8 gms

0 - 16 x 6 = 96 gms

160 gms

Gives

N - 14 x 2 = 28 gms

0 - 16 x 2 = 32 gms

H - 4 x 1 + 16 x 4= 64 gms

160 gms NH4NO3 = 32 GMS O2

12.6 GMS = X GMS

[ Unitary method ]

160/12.6 = 32/x

= 2.52 gms

160 gms NH4NO3 = 64 gms h20

12.6gms = x gms

160/12.6 = 64/x

= 5.04 gms

Is that correct???????????/

im a 14 year old indian by the way

lol

#3

what your doing wrong is asking the pit......except the first response...he looks like knows what hes talking about

#4

2NH4NO3 --------> 2N2 + O2 + 4H20

So, you're given 12.6 g of NH4NO3 and asked to find the g for each of the products.

N - 14 x 4 = 56gms

H - 4 x 2 = 8 gms

0 - 16 x 6 = 96 gms

160 gms

Gives

N - 14 x 2 = 28 gms

0 - 16 x 2 = 32 gms

H - 4 x 1 + 16 x 4= 64 gms

160 gms NH4NO3 = 32 GMS O2

12.6 GMS = X GMS

[ Unitary method ]

160/12.6 = 32/x

= 2.52 gms

160 gms NH4NO3 = 64 gms h20

12.6gms = x gms

160/12.6 = 64/x

= 5.04 gms

Is that correct???????????/

im a 14 year old indian by the way

lol

why that is correct my little indian friend

#5

2NH4NO3 --------> 2N2 + O2 + 4H20

So, you're given 12.6 g of NH4NO3 and asked to find the g for each of the products.

Now, I know how to do this (at least I thought so) but I'm not getting the right answers except for the weight of N2 (4.41 g). Yes I am looking at the mol ratio so that when I go from the # of mol of NHaNO3 to O2 I divide it by 2..but I'm just not getting the right answers..the hell?

well u didnt give much to work off but:

make sure you carry it out in these steps:

1) write it out the equation balanced with state symbols

2) right the mole ratios under each one (like 2mol. for 2N2)

3) substitute in the molar masses, checking to see whether its balanced

4) then get the first one to equal 1 in molar mass terms (i.e divide each thing by the molar mass of the first one)

5) times it by 12.6

6) connect it back to the question..

in my head that works.. just make sure u connect it back to the question.. tbh, it isnt that hard.

#6

what grade are you in??? cause i think theyre driving us nuts by teaching us this in 10th grade :S maybe just me whatever

#7

Yeah that way did work for me, I don't think I've ever crossed multiplied for this type of question.

And I'm in first year uni, so this is easy stuff, infact a review, it's just been awhile for me.

And I'm in first year uni, so this is easy stuff, infact a review, it's just been awhile for me.