#1
ok heres the question its quite long and is bugging the hell outta me:

excess N2 was reacted with 1 mol F2 under suitable conditions to give 24 dm^3 (measured at room temp/ pressure) of a colourless gas, [A]. Reaction of 12dm^3 of [A] with an additional 24 dm^3 of F2 in a sealed vessel at room temp pressure led to a decrease in pressure to 2/3 atm and the formation of a single gaseous product , which contains 19.7% N.

Sufficient O2 was then introduced to bring the pressure to 1 atm. After passing an electric discharge throught the vessel , the pressure dropped to 2/3 atm and a single producct [C] was formed (boiling point -88 degrees). equal volumes of [c] and B(F3) were reacted to give a single crystaline product [D] which contains 9 % N

What the hell is [A], , [c] and [D]????
"Like a midget at a urinal, I was going to have to stay on my toes"

"Like a blind man at an orgy, I was going to have to feel my way through"

Last edited by YngwieJnr at Oct 25, 2008,
#3
im an english major...
Remember through sounds
Remember through smells
Remember through colors
Remember through towns
-Modest Mouse, "Novocaine Stain"
#4
wow no ones corrected my grammar yet it should be what ARE [A], ,[C] and [D]
"Like a midget at a urinal, I was going to have to stay on my toes"

"Like a blind man at an orgy, I was going to have to feel my way through"

#5
Man, I took Chemistry last year and I can't remember a single thing from that class. Your post is gibberish to me.
#6
i believe its concentrations [C]^c[D]^d / [A]^a^b, where a,b,c,d are the coefficients of the chemicals after they are balanced.
#8
? Just take off your pants, there is no need for pants in science.
■■■
'member The Pit of 10'? oH, I 'member!


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#9
ok heres the question its quite long and is bugging the hell outta me:

excess N2 was reacted with 1 mol F2 under suitable conditions to give 24 dm^3 (measured at room temp/ pressure) of a colourless gas, [A]. Reaction of 12dm^3 of [A] with an additional 24 dm^3 of F2 in a sealed vessel at room temp pressure led to a decrease in pressure to 2/3 atm and the formation of a single gaseous product , which contains 19.7 N.

Sufficient O2 was then introduced to bring the pressure to 1 atm. After passing an electric discharge throught the vessel , the pressure dropped to 2/3 atm and a single producct [C] was formed (boiling point -88 degrees). equal volumes of [c] and B(F3) were reacted to give a single crystaline product [D] which contains 9 % N

What the hell is [A], , [c] and [D]????

24 dm^3 (or 24 liter) is the volume that 1 mole of gas occupies under normal pressure.
A)So 1 mole of F2 reacts with nitrogen to give 1 mole of a compound. Therefor it is likely to have 2 fluorine atoms in it and this would mean N2F2 (F-N=N-F).
B)You add 4 fluorine molecules per N2F2 which would become N2F6 which dissociates into NF3 (nitrogen trifluoride).
C) you add 2 oxygen atoms per 2 NF3 molecules, likely each NF3 molecule oxidizes one oxygen molecule to generate dioxygendifluoride and difluorohydrazine (F4N2, single bond between the oxygens)
EDIT: i am doubting C as well now, FNO could also be formed somehow? Looks like I need twice the amount of oxygen in the reaction above. Edit2: **** it, apparantly you can oxidize NF3 itself to NF3O, nitrogentrifluoride oxide which can form a borotrifluoride complex in D.
D)This is a NF3O-BF3 complex most likely

Anyway, the best thing is that apparently nitrogen won't react with fluorine by itself.
Last edited by Dylan_IE at Oct 25, 2008,