I got a project where I'm suppose to write a paragraph on how many times you could "stretch one pound of gold around the world"... wtf!! Anybody ever heard of this b4?
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http://en.wikipedia.org/wiki/Metal_leaf
http://en.wikipedia.org/wiki/Goldbeating

At a thickness of 100 nm, one square metre of gold leaf corresponds to 0.1 cubic centimetre or just 2 grams of gold. In Imperial measurements, one ounce (28.34 g) of gold corresponds to about 200 square feet (about 20 m2) of gold leaf.

edit: if you make a square one nanometre * one nanometre wire out of 1 pound of gold it'd be enough to go 5.8 times round the equator

Last edited by seljer at Oct 27, 2008,
okay.
Find out how much gold (dimensions) there is in a pound, then find what the dimensions are of a gold atom, and how many atoms there are in a pound of gold... maybe...
Have fun with that
well, assuming you can stretch it out to a strand that is only one atom wide, im guessing a lot of times.

figure out approximately how many atoms are in a pound of gold, and then figure out how long it would be if you stretched that out.

EDIT: looks like im not the only one with that idea.

DO IT!
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figure out how many grams are in a mole of gold. (107.87 grams i believe). Convert pounds into kg then divide kg by 107.87 g. That will give the moles of gold, multiply the moles times 6 X 10^23 and that will give you the number of atoms in a pound of gold. Then figure out the diameter of an atom and multiply it by the number of atoms.Then divide by the circumference of the earth. There you go theres you paragraph.
It's actually pretty simple.
You have a weight (pound), so you can calculate how many atoms you have. Just use the molecular weight of gold: if a gram of gold has this many molecules, then a pound of gold has that many.
Then, you have a number of atoms. Suppose you use all these atoms to form a very long wire, like beads on a string. If you know the diameter of an atom of gold (look it up), you can calculate the length of the "beaded string" easily by the number of "beads". E.g. beads with 1 inch diameter, 10 beads make a 10 inch string. Simple!

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figure out how many grams are in a mole of gold. (107.87 grams i believe). Convert pounds into kg then divide kg by 107.87 g. That will give the moles of gold, multiply the moles times 6.02 X 10^23 and that will give you the number of atoms in a pound of gold. Then figure out the diameter of an atom and multiply it by the number of atoms.Then divide by the circumference of the earth. There you go theres you paragraph.

fixed.
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Quote by Guitarpilot
figure out how many grams are in a mole of gold. (107.87 grams i believe). Convert pounds into kg then divide kg by 107.87 g. That will give the moles of gold, multiply the moles times 6 X 10^23 and that will give you the number of atoms in a pound of gold. Then figure out the diameter of an atom and multiply it by the number of atoms.Then divide by the circumference of the earth. There you go theres you paragraph.

Listen to this ^^ guy. That's your answer right there. I've had similar questions in high school math. Has to do with using conversion equations from atoms to moles to grams and dimensions.
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I got "101320479607422126.97326927431139" times.. I know for a fact that is wrong, because I didn't know how to convert... but she is a cool teacher and she'll give me credit anyways lol
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Quote by touji-za-nai
I got "101320479607422126.97326927431139" times.. I know for a fact that is wrong, because I didn't know how to convert... but she is a cool teacher and she'll give me credit anyways lol

If you can tell me the width of an atom of gold then I will work the rest out for you, I've been trying to find it but I can't. I'll even show you all my working!
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If you can tell me the width of an atom of gold then I will work the rest out for you, I've been trying to find it but I can't. I'll even show you all my working!

I just guessed with .1 nano meters
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Chemistry sucks.

That and biology.
Im pretty sure you need to find how many atoms are in the gold first.

So do this
weight of the gold you have g x (1mol/avg mass) x (6.02x10^23/1)

Then figure out the distance of...idk
That relates to maleability, and gold is very malleable...
AROUND THE WORLD

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I got "101320479607422126.97326927431139" times.. I know for a fact that is wrong, because I didn't know how to convert... but she is a cool teacher and she'll give me credit anyways lol

Dimensional analysis FTW.
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fixed.

Thanks dude. Thought i might have ****ed that number up.