#1

its chemisty heres the question

20. what is the volume at STP of these gases?

3.20 x 10 exponent -23 mol CO2

or can anyone help me on my homework on aim please?

20. what is the volume at STP of these gases?

3.20 x 10 exponent -23 mol CO2

or can anyone help me on my homework on aim please?

*Last edited by GraveSs at Oct 27, 2008,*

#2

32000000000000000000000000000000000000000000000000000000000000000 mL cubed

Bitches

Bitches

#3

ohh hmmmm this is so long ago i did this.

22.4 liters

^ that is the volume of 1 mole of gas at STP.

although i'm not sure what you are asking exactly ...what gases? and whats with the number?

22.4 liters

^ that is the volume of 1 mole of gas at STP.

although i'm not sure what you are asking exactly ...what gases? and whats with the number?

*Last edited by Skierinanutshel at Oct 27, 2008,*

#4

scott weiland?

#5

can someone show me the work?

#6

one mole of any gas at STP is 22.4 L.

I dont know what 3.2 x 10^-23 is.

is that the number of moles you have to find the volume for?

I dont know what 3.2 x 10^-23 is.

is that the number of moles you have to find the volume for?

#7

can someone show me the work?

you better start making some sense, and i havent done any "work" yet so there is none to show

#8

scott weiland?

Haha, just what I was thinking.

#9

A.Over 9000?

B.Under 5 billion?

C.Less than infinity?

D.12?

E.All of the above

F.None of the above

That's right, there are six options, not four.

B.Under 5 billion?

C.Less than infinity?

D.12?

E.All of the above

F.None of the above

That's right, there are six options, not four.

#10

whoops iw rote the question wrong i edited it

#11

just take that number and multiply by 22.4 liters than do any conversions (L, mL) needed

#12

(3.20 x 10^-23) x ((22.4)/(6.02 x 10^23))

#13

(3.20 x 10^-23) x ((22.4)/(6.02 x 10^23))

this.

#14

what about for this question

21. assuming STP, how many moles are in these volumes?

a.67.2mL SO2

B.0.880 L He

c.1.00 X 10^3 L C2H6

21. assuming STP, how many moles are in these volumes?

a.67.2mL SO2

B.0.880 L He

c.1.00 X 10^3 L C2H6

#15

A.Over 9000?

B.Under 5 billion?

C.Less than infinity?

D.12?

E.All of the above

F.None of the above

That's right, there are six options, not four.

Me and my highly trained team of scientists have figured the answer is A: Over 9000!

#16

we gave you the basic formula, do the algebra, and figure it out for yourself. that way you can understand how to do these kind of gas stoich problems on a test

#17

but i get what STP is

#18

but i get what STP is

STP is just a set of standardized conditions.

you should use the formula you were given earlier, change around the unknown x value, and solve

#19

pay me e-money.

XD

XD

#20

PV=nRT.

P=1 atm

n=3.2*10^(-23) mol

R=.082(L*atm)/(mol*k)

T=298 K

V=(nRT)/P

alright?

I'm assumming you're just doing ideal gases if you don't know that, but you could do van der waal's equation too.

P=1 atm

n=3.2*10^(-23) mol

R=.082(L*atm)/(mol*k)

T=298 K

V=(nRT)/P

alright?

I'm assumming you're just doing ideal gases if you don't know that, but you could do van der waal's equation too.