Okay, lets say you have the equation
125 = 5^x
i know from common sense that x = 3, but how would you solve it algebraically? I know its something involving logarithms and whatnot, but i have no idea what that is...help?
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log (to the base 5) 125 = x =3
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afterward i thought about it and was like "wow, i just jerked off to a chubby girl sucking off a horse. i'm disgusting".

then i watched that segment again
125 = 5^x
ln(125) = xln(5)
ln(125)/ln(5) = x
3=x
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log (to the base 5) 125 = x =3

what does to the base 5 mean? how would one do this on a calculator?
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you can be jesus.

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most useless response i think i have ever seen on any forum ever.

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i pity the fool who opens a math thread
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uhhh....flying cows??
Lets say you have log(base 5) 7

In your calculator, divide log 7 by log 5

And that's it! It is called the Change of Base formula.
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Easiest way is to just take the log of both sides so log125=xlog5
so x=log25/log5