Hey Pit, I was just wondering who could answer a quick AP Calculus problem.

It has to do with Derivatives of Exponential functions; I know that the derivative of (e^x)=(e^x) , but I don't know what to do with the coefficients and such, when dealing with more complex problems.

Basically, I'd like to know how to go about doing a problem like:

Find an algebraic expression for f'(x) given f(x)=(e^5)-4e^x

Any help is appreciated.
(by the way, it's hard to see the f prime symbol with this font, but the problem is finding the derivative of the function).

Sorry, mistyped the first time.
Last edited by manmanman133 at Nov 9, 2008,
Quote by magic medicine
there is no x in that expression so the derrivative is zero

Sorry, a typo, it's corrected now.
math thread
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This is how you do it...

f '(x)=u'e^u

So for your problem...


(e^5) -> u=5 and u' =0
So 0(e^5)=0

-4e^x -> u=x and u' =1
So 1(-4e^x)=-4(e^x)

Therefore the answer is 0-4(e^x)
Last edited by MetropolisPt3 at Nov 9, 2008,
I used to think that tabs was the closest thing to math the Pit could do