#1

^2 means squared.

solve

a^2 = 1 + 9 -3y -3y +y^2 - 2(1)(3-y)cos60

that would be sick of you answered it and told me how you did it, or just like showed your work.

(come on pit, be cool)

solve

a^2 = 1 + 9 -3y -3y +y^2 - 2(1)(3-y)cos60

that would be sick of you answered it and told me how you did it, or just like showed your work.

(come on pit, be cool)

#2

You should pay attention in class, and not "txt" your bff.

#3

you appear to have more than one variable

#4

i do,

and i dont have a cell lmao.

its just confusing cuz the (3-y) is messing me up.

and i dont have a cell lmao.

its just confusing cuz the (3-y) is messing me up.

#5

#6

7.35

#7

Whu..

*head explodes*

*head explodes*

#8

I'd help you, but I just had all my friends over for a trigonometry party. So I'm kind of burnt out on it, y'know.

#9

any one at all???

come on , i no you all pasted grade 11

come on , i no you all pasted grade 11

#10

i do,

and i dont have a cell lmao.

its just confusing cuz the (3-y) is messing me up.

just distribute the cos(60) and -2(1) into it

#11

4-6y+y^2-2y(cos60)=a^2

a^2-4=-6y+y^2-2y(cos60)

(a^2-4)/2=-3y+(1/2y^2)-y(cos60)

I got that far but think I ****ed up the beginning, (I) can't get further without a value for one of the variables.

a^2-4=-6y+y^2-2y(cos60)

(a^2-4)/2=-3y+(1/2y^2)-y(cos60)

I got that far but think I ****ed up the beginning, (I) can't get further without a value for one of the variables.

#12

what do u mean?

#13

Sorry mate, I cheated, lied, and raped my way through grade 11 and 12 maths. And I didn't even pass one of my grade 12 courses.

#14

just distribute the cos(60) and -2(1) into it

yeah.

i dont have a calculator or i'd do it. i dont remember the cos crap off the top of my head. i just did some algebra and got down to

a^2 = 16 + -4y + y^2 (cos60)

i saved the cos for last obviously. i just took a stab, probably didnt do it right, but i hope i got somewhere.

meh. i needed something to do.

#15

i think you might be right archetype00

#16

hold on im working it

#17

i think you might be right archetype00

he is

gj mate!

#18

sweet, thanks. lol

#19

i think you might be right archetype00

its just simple algebra then. just add like terms. this is what i did. i hope you can see the differences i just broke it down a bit.

a^2 = 1 + 9 + -3y + -3y + y^2 - 2(1) (3-y) (cos60)

a^2 = 10 + -3y + -3y + y^2 - 2(3-y) (cos60)

a^2 = 10 + -6y + y^2 + -2y(3-y) (cos60)

a^2 = 10 + -6y + y^2 + -6 + 2y (cos60)

a^2 = 16 + -4y + y^2 (cos60)

thats as far as i got

by the time i finished typing this, you probably have the answer tho.

EDIT-

i didnt think i was right hahaha. glad i could be of assistance. I havent even taken trig yet XD

#20

any one at all???

come on , i no you allpastedgrade 11

And I know you failed English class.

#21

And I know you failed English class.

out of that entire statement, that's the only grammatical error you could find?

i know someone else who didn't pass english...

#22

You're an idiot.

*reported*

*reported*

#23

^2 means squared.

solve

a^2 = 1 + 9 -3y -3y +y^2 - 2(1)(3-y)cos60

that would be sick of you answered it and told me how you did it, or just like showed your work.

(come on pit, be cool)

a^2 = 1 + 9 -3y -3y +y^2 - 2(1)(3-y)cos60

a^2 = 10 - 6y + y^2 - (6 - 2y).cos60º

a^2 = 10 - 6y + y^2 - (6 - 2y).1/2

a^2 = 10 - 6y + y^2 - 3 + y

a^2 = y^2 - 5y + 7

y^2 - 5y + (7 - a^2) = 0

And use quadratic formula to solve for y if that's what you want ..