#1
OK brainy guitarists I just want to know if this is correct

Find the volume of the region created between y=x^2 and y=x about the x-axis using the shell method
I got-------> pi/6

Find the volume of the region created between y=x^2 and y=x about the y-axis using the disk method
I got -------> (2(pi))/15

Should they both be the same?
#2
they wont necessarily be the same but i cant remember well enough how to do it to tell you if those numbers are right
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#3
yes it should. it doesn't matter what method you use because your trying to find the same thing, the volume of the region created between y=x^2 and y=x
#4
I didn't have time to work this out. But I do know that they are not the same. They are the opposite. Basically, the first is the top half (or 3/4 or 5/8... whatever) of y=x^2, and the second one is the bottom half of y=x^2
Gear:
Gibson Explorer (white)
Schecter C-1 Classic
Fender SuperSonic 112
Visual Sounds Jekyll & Hyde
EHX No.1 Echo
Ibanez Weeping Demon
#7
Quote by LedZepFan2000
OK brainy guitarists I just want to know if this is correct

Find the volume of the region created between y=x^2 and y=x about the x-axis using the shell method
I got-------> pi/6

Find the volume of the region created between y=x^2 and y=x about the y-axis using the disk method
I got -------> (2(pi))/15

Should they both be the same?

Shouldn't it be infinite since Y=X^2 is a continuous function? Or is that only for area?
PPPPPPPOSTFINDER
#9
the volumes will not be the same, when you revolve the area between the two curves about either the y axis or the x axis you get a different 3d shape, so they have diff volume.

if it helps, draw a picture of each, and you'll see that they are different